Well, I'm not entirely sure what you're asking. In this reaction equation:
Ba + ZnSO4 --> BaSO4 + Zn, barium is a reactant. The equation is balanced as is, so everything is in a nice even 1-to-1 molar ratio, making stoichiometric calculations pretty easy. That's about all I can tell you though, based on the limited information present.
HI, I'm Elham .As i found it's: ZnSO4+Br(NO3)2..........Zn(NO3)2 +BrSO4
double replacement
Assuming you have given a complete equation, no. It requires oxygen as a reactant and will always have CO2 and H2O as products. Plus, combustion reactions typically involve carbon based elements as reactants.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
Ba^2+(aq) + 2Cl^-(aq) + Zn^+2(aq) + SO_4^2-(aq) --> BaSO_4(s) + Zn^2+(aq) + 2Cl^-(aq)
HI, I'm Elham .As i found it's: ZnSO4+Br(NO3)2..........Zn(NO3)2 +BrSO4
BaCl2 + K2So4 ----> BaSo4 + 2 KCl
double replacement
The chemical equation is:Zn + SnSO4 = ZnSO4 + Sn
Zn + CuSO4 --> ZnSO4 + Cu
Assuming you have given a complete equation, no. It requires oxygen as a reactant and will always have CO2 and H2O as products. Plus, combustion reactions typically involve carbon based elements as reactants.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
Ba^2+(aq) + 2Cl^-(aq) + Zn^+2(aq) + SO_4^2-(aq) --> BaSO_4(s) + Zn^2+(aq) + 2Cl^-(aq)
Ba + H2SO4 ---> BaSO4 + H2
copper (II) sulfate is CuSO4 ; Zinc sulfate is ZnSO4 Zn + CuSO4 --> ZnSO4 + Cu
The reactants are C8H18 and oxygen.
BaCO3 + H2SO4 --> BaSO4 + CO2 + H2O