BaCl2 + K2SO4 --> BaSO4 + 2KCl
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
Well, well, well, aren't we feeling fancy with our chemistry questions? The balanced equation for barium chloride and potassium sulfate is BaCl2 + K2SO4 → BaSO4 + 2KCl. Don't worry, I won't charge you extra for the chemistry lesson!
When they react K2SO4 and BaBr2 they'll give 2KBr and BaSO4: SO42-aq + Ba2+aq ---> (BaSO4)s ('s' = solid = precipitating bariumsulfate) 2K+ and Ba2+ are spectator ions (all 'aq' = hydrated in solution)
KCl + Ba(SO4) → NR (no reaction) Potassium and chloride don't react, and BaSO4 does not dissolve. Only the opposite reaction would take place: Sulfate and barium from other sources are precipitating to solid. SO4-2(aq) + Ba2+(aq) → BaSO4(s)
The chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium sulfate (K2SO4) is Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3. It forms barium sulfate (BaSO4) and potassium nitrate (KNO3) as the products.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
Well, well, well, aren't we feeling fancy with our chemistry questions? The balanced equation for barium chloride and potassium sulfate is BaCl2 + K2SO4 → BaSO4 + 2KCl. Don't worry, I won't charge you extra for the chemistry lesson!
The reaction between barium chloride and potassium sulfate results in the formation of insoluble barium sulfate and soluble potassium chloride. This is a double displacement reaction where the cations and anions switch partners. The balanced chemical equation for this reaction is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The net ionic equation for the reaction between potassium sulfate (K2SO4) and barium chloride (BaCl2) is: 2K+ (aq) + SO4^2- (aq) + Ba^2+ (aq) + 2Cl- (aq) → 2K+ (aq) + 2Cl- (aq) + BaSO4 (s). In this equation, the spectator ions (K+ and Cl-) are removed to show only the species that are involved in the chemical change.
Here is the skeleton equation: (NH4)2SO4 + KOH --> K2SO4 + NH3 + H2O And here is the balanced equation: (NH4)2SO4 + 2KOH --> K2SO4 + 2NH3 + 2H2O Here is the net ionic equation: NH4+ (aq) + OH- (aq) ---> NH3 (g) + H2O (l)
When they react K2SO4 and BaBr2 they'll give 2KBr and BaSO4: SO42-aq + Ba2+aq ---> (BaSO4)s ('s' = solid = precipitating bariumsulfate) 2K+ and Ba2+ are spectator ions (all 'aq' = hydrated in solution)
KCl + Ba(SO4) → NR (no reaction) Potassium and chloride don't react, and BaSO4 does not dissolve. Only the opposite reaction would take place: Sulfate and barium from other sources are precipitating to solid. SO4-2(aq) + Ba2+(aq) → BaSO4(s)
Molecular:Bacl2(aq)+K2SO4(aq)-->BaSO4(s)+2KCl(aq)Total Ionic:Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)Net Ionic:Ba+2(aq) + SO4-2(aq)-->BaSO4(s)The ionic equation would have the ionic charges of each compound/element/or whatever. Ba^+2 CL^- for the first.. etc. You do the 'criss-cross' method to determine the ionic charges, and write that into the equation.This is a double-replacement precipitation type of reaction.
When barium chloride reacts with potassium sulfate, a double displacement reaction occurs. Barium sulfate and potassium chloride are formed as products. BaCl2(aq) + K2SO4(aq) → BaSO4(s) + 2KCl(aq). Barium sulfate is insoluble in water and precipitates out as a white solid.
The chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium sulfate (K2SO4) is Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3. It forms barium sulfate (BaSO4) and potassium nitrate (KNO3) as the products.