BaCl2 + K2SO4 --> BaSO4 + 2KCl
BaCl2 + K2So4 ----> BaSo4 + 2 KCl
Iron(III)Sulfate and Barium Iodide Reaction:Fe2(SO4)3 + 3BaI2 → 2FeI3 + 3BaSO4
When they react K2SO4 and BaBr2 they'll give 2KBr and BaSO4: SO42-aq + Ba2+aq ---> (BaSO4)s ('s' = solid = precipitating bariumsulfate) 2K+ and Ba2+ are spectator ions (all 'aq' = hydrated in solution)
K2CrO4 + BaSo4 ----------> BaCrO4 (Precipitate) + K2SO4 Potassium Barium Barium Potassium Chromate Sulphate Chromate Sulphate It Is A Double Displacement Reaction
KCl + Ba(SO4) → NR (no reaction) Potassium and chloride don't react, and BaSO4 does not dissolve. Only the opposite reaction would take place: Sulfate and barium from other sources are precipitating to solid. SO4-2(aq) + Ba2+(aq) → BaSO4(s)
BaCl2 + K2So4 ----> BaSo4 + 2 KCl
BaCl2 + K2SO4 = BaSO4 + 2 KCl .
BaCl2+K2SO4=2KCl+BaSO4
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The net ionic equation for the reaction between potassium sulfate (K2SO4) and barium chloride (BaCl2) is: 2K+ (aq) + SO4^2- (aq) + Ba^2+ (aq) + 2Cl- (aq) → 2K+ (aq) + 2Cl- (aq) + BaSO4 (s). In this equation, the spectator ions (K+ and Cl-) are removed to show only the species that are involved in the chemical change.
Iron(III)Sulfate and Barium Iodide Reaction:Fe2(SO4)3 + 3BaI2 → 2FeI3 + 3BaSO4
Here is the skeleton equation: (NH4)2SO4 + KOH --> K2SO4 + NH3 + H2O And here is the balanced equation: (NH4)2SO4 + 2KOH --> K2SO4 + 2NH3 + 2H2O Here is the net ionic equation: NH4+ (aq) + OH- (aq) ---> NH3 (g) + H2O (l)
Molecular:Bacl2(aq)+K2SO4(aq)-->BaSO4(s)+2KCl(aq)Total Ionic:Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)Net Ionic:Ba+2(aq) + SO4-2(aq)-->BaSO4(s)The ionic equation would have the ionic charges of each compound/element/or whatever. Ba^+2 CL^- for the first.. etc. You do the 'criss-cross' method to determine the ionic charges, and write that into the equation.This is a double-replacement precipitation type of reaction.
2 k + h2so4 = k2so4 + h2
Potassium sulphate - K2SO4; the precipitate is BaSO4 - the reaction is frequently used in gravimetric analysis.
When they react K2SO4 and BaBr2 they'll give 2KBr and BaSO4: SO42-aq + Ba2+aq ---> (BaSO4)s ('s' = solid = precipitating bariumsulfate) 2K+ and Ba2+ are spectator ions (all 'aq' = hydrated in solution)
It's K + H2SO4= K2SO4 +H2