When they react K2SO4 and BaBr2 they'll give 2KBr and BaSO4:
SO42-aq + Ba2+aq ---> (BaSO4)s ('s' = solid = precipitating bariumsulfate)
2K+ and Ba2+ are spectator ions (all 'aq' = hydrated in solution)
Ba + SO4 will give you BaSO4 Ba + Br will give you BaBr2The first equation is barium sulfate and the second one is barium bromide.
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
yes!!
CuSO4 + BaCl2 --> CuCl2 + BaSO4
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
Ba + SO4 will give you BaSO4 Ba + Br will give you BaBr2The first equation is barium sulfate and the second one is barium bromide.
2 KBr + BaI2 ----> 2 KI + BaBr2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
BaCl2+K2SO4=2KCl+BaSO4
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
Barium sulphate to barium sulphate is NO CHANGE!
The net ionic equation for the reaction between potassium sulfate (K2SO4) and barium chloride (BaCl2) is: 2K+ (aq) + SO4^2- (aq) + Ba^2+ (aq) + 2Cl- (aq) → 2K+ (aq) + 2Cl- (aq) + BaSO4 (s). In this equation, the spectator ions (K+ and Cl-) are removed to show only the species that are involved in the chemical change.
it remains yellow i think me
yes!!
The question statement is true (except that the first instance, but not the second instance, of "dissolved" is misspelled.)
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