Unbalanced: KBr + BaI2 --> KI + BaBr2
Balanced: 2KBr + BaI2 --> 2KI + BaBr2
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
KBr + H2O = Kaq+ Braq- Haq+ OHaq-
Lead nitrate and potassium bromide react to form lead(II) bromide and potassium nitrate. This chemical reaction is a double displacement reaction where the cations and anions exchange partners to form the new compounds.
The balanced chemical equation for potassium bromide is KBr(s) --> K+(aq) + Br-(aq).
The chemical equation for the preparation of ammonium bromide using potassium bromide and ammonium sulfate is: 2KBr + (NH4)2SO4 -> 2NH4Br + K2SO4
2 KBr + BaI2 ----> 2 KI + BaBr2
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The balanced chemical equation for this reaction is: 2KBr + Al(NO3)3 → 2KNO3 + AlBr3
Potassium bromide and fluorine would react to form potassium fluoride and bromine gas. The balanced chemical equation for this reaction is 2KBr + F2 -> 2KF + Br2.
The balanced chemical equation for the reaction where potassium (K) replaces magnesium (Mg) in magnesium bromide (MgBr2) to form potassium bromide (KBr) and magnesium (Mg) is: [ 2K + MgBr_2 \rightarrow 2KBr + Mg ] This equation indicates that two moles of potassium react with one mole of magnesium bromide to produce two moles of potassium bromide and one mole of magnesium.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Potassium bromide is basically a chemical.
The balanced equation for potassium bromide (KBr) and ammonium chloride (NH4Cl) is: KBr + NH4Cl → KCl + NH4Br
Potassium bromide has the formula KBr and it contains one atom of Potassium (K) and one atom of Bromine (Br).
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)