Ba^2+(aq) + 2Cl^-(aq) + Zn^+2(aq) + SO_4^2-(aq) --> BaSO_4(s) + Zn^2+(aq) + 2Cl^-(aq)
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The net ionic equation for the reaction is: Ba^2+(aq) + AsO4^3-(aq) → BaAsO4(s). This equation shows the formation of solid barium arsenate from the aqueous ions of barium and arsenate present in the reactants.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
The balanced chemical equation for the reaction is: Zn(s) + CuSO4(aq) -> ZnSO4(aq) + Cu(s)
first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq) Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The net ionic equation for the reaction is: Ba^2+(aq) + AsO4^3-(aq) → BaAsO4(s). This equation shows the formation of solid barium arsenate from the aqueous ions of barium and arsenate present in the reactants.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The chemical equation is:Zn + SnSO4 = ZnSO4 + Sn
Zn + CuSO4 --> ZnSO4 + Cu
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
The balanced chemical equation for the reaction is: Zn(s) + CuSO4(aq) -> ZnSO4(aq) + Cu(s)
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
2K3PO4 + 3BaCl2 -> Ba3(PO4)2 + 6KCl
first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck