This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
The answer is TWO (2)Na2CO3 + CaCl2 --> 2 NaCl + CaCO3
The word equation for silver nitrate plus sodium chloride is "silver nitrate + sodium chloride → silver chloride + sodium nitrate". The symbol equation for this reaction is "AgNO3 + NaCl → AgCl + NaNO3".
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
To balance the chemical equation K3PO4 + BaCl2, you would first write out the unbalanced equation: K3PO4 + BaCl2 → ? To balance it, you would need to ensure that the same number of atoms of each element are present on both sides of the equation. This means adjusting the coefficients in front of each compound until balanced.
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:BaCl2 + H2SO4 ------> BaSO4 + HClThen work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?BaCl2 + H2SO4 -------> BaSO4 + 2HCl
HCl + NaOH = H2O + NaCl is already balanced.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
2K3PO4 + 3BaCl2 -> Ba3(PO4)2 + 6KCl