2K3PO4 + 3BaCl2 -> Ba3(PO4)2 + 6KCl
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To balance the chemical equation K3PO4 + BaCl2, you would first write out the unbalanced equation: K3PO4 + BaCl2 → ? To balance it, you would need to ensure that the same number of atoms of each element are present on both sides of the equation. This means adjusting the coefficients in front of each compound until balanced.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
The balanced equation for CuMnO4 + K3PO4 would be: CuMnO4 + 2K3PO4 → Cu3(PO4)2 + 3KMnO4 So, the set of coefficients that would balance this equation is 1:2:1:3.
The coefficient in front of water in the balanced chemical equation for the reaction between H3PO4 and KOH to form K3PO4 and water is 4. This means that four molecules of water are formed in this reaction for every one molecule of H3PO4 and three molecules of KOH that react.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
When barium chloride (BaCl2) reacts with fluorine (F2), it forms barium fluoride (BaF2) and chlorine gas (Cl2). The balanced chemical equation for this reaction is: BaCl2 + F2 -> BaF2 + Cl2.
The reaction between FeSO4 (iron(II) sulfate) and BaCl2 (barium chloride) will produce a precipitate of barium sulfate (BaSO4) and iron(II) chloride (FeCl2) in solution. The balanced chemical equation for the reaction is: FeSO4 + BaCl2 -> BaSO4 + FeCl2.
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS