I suppose it would be BaF2 + Cl2.
To find the mass of F2 needed to produce 120 g of PF3 at a yield of 78.1%, we first calculate the theoretical mass of PF3 that would require 100% yield. The molar mass of PF3 is approximately 88 g/mol. Therefore, the theoretical mass of PF3 produced from 120 g at 78.1% yield is ( 120 , \text{g} / 0.781 = 153.5 , \text{g} ). Assuming the reaction is balanced as ( P + \frac{3}{2} F_2 \rightarrow PF_3 ), we can then determine that the stoichiometry requires 1 mole of F2 for every mole of PF3. Hence, the mass of F2 needed is calculated using the molar mass of F2 (approximately 38 g/mol), resulting in approximately 60 g of F2 needed to produce the required PF3.
This reaction is:Ba(ClO3)2 = BaCl2 + O2
First, calculate the molar mass of PF3: P = 30.97 g/mol, F = 19.00 g/mol, so PF3 = 30.97 + (3 * 19.00) = 88.97 g/mol. Given that the reaction is 76.5% yield, the actual mass of PF3 produced is 186 g / 0.765 = 242.75 g. From the balanced equation, 6 moles of F2 are needed to produce 4 moles of PF3. Therefore, the molar ratio is 6:4. Calculate the moles of PF3 produced and then find the moles of F2 needed. Finally, convert moles of F2 to grams.
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
Barium chloride or BaCl2
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
Denoting ff as f2 etc, f2 + f + f3 + f = f3 + f2 + 2f
The coefficient for F2 in the chemical equation Ca + F2 → CaF2 is 1.
Probably as a Displacement reaction
Barium chloride; BaCl2
F2 < F2- < F2+. This is because F2 has no extra electrons or missing electrons, while F2- has an extra electron making it more stable than F2. F2+ is the least stable as it has lost an electron, creating an electron deficiency.
the base is the substance which has settled down. it's BaSO4
The reaction between FeSO4 (iron(II) sulfate) and BaCl2 (barium chloride) will produce a precipitate of barium sulfate (BaSO4) and iron(II) chloride (FeCl2) in solution. The balanced chemical equation for the reaction is: FeSO4 + BaCl2 -> BaSO4 + FeCl2.
Its already balanced.
yes, because it stinks! LOL haha