you do the hoky poky and turn your self around....thats what its all about :D
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:BaCl2 + H2SO4 ------> BaSO4 + HClThen work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?BaCl2 + H2SO4 -------> BaSO4 + 2HCl
The reaction of FeSO4 (iron(II) sulfate) with K3PO4 (potassium phosphate) results in the formation of Fe3(PO4)2 (iron(II) phosphate) and K2SO4 (potassium sulfate).
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
Barium has a 2+ charge while chlorine has a 1- charge, so they combine in a 1:2 ratio to form the compound barium chloride (BaCl2). In this compound, the two chloride ions balance the 2+ charge of the barium ion.
2K3PO4 + 3BaCl2 -> Ba3(PO4)2 + 6KCl
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The balanced equation for CuMnO4 + K3PO4 would be: CuMnO4 + 2K3PO4 → Cu3(PO4)2 + 3KMnO4 So, the set of coefficients that would balance this equation is 1:2:1:3.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:BaCl2 + H2SO4 ------> BaSO4 + HClThen work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?BaCl2 + H2SO4 -------> BaSO4 + 2HCl
The compound formed between barium and chlorine would be barium chloride (BaCl2). In this compound, barium has a +2 charge and chlorine has a -1 charge, so two chlorine atoms are needed to balance the charge of one barium atom.
The reaction of FeSO4 (iron(II) sulfate) with K3PO4 (potassium phosphate) results in the formation of Fe3(PO4)2 (iron(II) phosphate) and K2SO4 (potassium sulfate).
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
Probably as a Displacement reaction
Barium chloride; BaCl2