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A horses velocity changes from 0 m s to 10 m s 5 seconds later What is the horses average acceleration?
2 meter/seconds squared
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
If i move forward 5 meters in 2 seconds. what is my velocity?
5/2 = 2.5 m/s; velocity is distance divided by time
How do you know an objects speed and velocity?
if the objects distance travelled and time is given then speed=distance/time eg- distance travelled 50 mtrs time taken 5 seconds speed 50/5 =10m/s velocity=u(initial velocity 0 for free falling objects) + at(acceleration x time)
11 ms in 5 seconds what is the acceleration?
It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5
What is a cars acceleration if it travels 0 to 55 miles per hour in 6 seconds?
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
What velocity does the student have after five seconds?
Velocity increases after 5 seconds
A horses velocity changes from 0 m s to 10 m s 5 seconds later What is the horses average acceleration?
2 meter/seconds squared
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
What is the accelaration 0 to 60 mph in seconds for 2010 Chevrolet camaro ss?
Between 4.5-5 seconds
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
What is the acceleration of an object that starts stopped and after 5 seconds is going 25mm per hour?
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
If i move forward 5 meters in 2 seconds. what is my velocity?
5/2 = 2.5 m/s; velocity is distance divided by time
A Kangaroo hops 60 m to the east in 5 seconds What is the kangaroo's velocity?
It's 60 divided by 5, Which is 12m/s east. Velocity is a vector for speed, since velocity has a direction and speed does not. Velocity has the SI units of meters per second. So you take the meters and divide by how many seconds to get your velocity.
How do you know an objects speed and velocity?
if the objects distance travelled and time is given then speed=distance/time eg- distance travelled 50 mtrs time taken 5 seconds speed 50/5 =10m/s velocity=u(initial velocity 0 for free falling objects) + at(acceleration x time)
What is the objects velocity after the 20 N force is applied for 5 seconds?
There is no answer to your question without knowing the direction of the velocity and of the force application.
