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Technically, equations are never perpendicular to one another. However, the equations of lines can result in their lines being perpendicular. Using y=mx+b, to have a perpendicular line, you have the negative reciprocal of m.
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What makes two linear equations either parallel or perpendicular to each other?
Depending on the value of the slope or gradient if its the same then they are parallel if its a reciprocal then they are perpendicular.
How can we tell if two lines are parallel perpendicular or neither just from their equations?
If the slope of the equations are the same then they are parallel If the slope of the equations are minus reciprocal then they are perpendicular If the slope of the equations are different then they are neither
What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?
If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.
What equations describes a line that is perpendicular to 2x plus 9y equals 9?
Any one of them that has a slope of 9/2 or 4.5
How do you know when two equations will be perpendicular?
When they meet at right angles when plotted on the coordinated grid.
Can two perpendicular equations have different y-intercepts?
If 2 equations are perpendicular to one another they can have different y-intercepts, depending on how they are situated on a (x,y) graph.
What makes two linear equations either parallel or perpendicular to each other?
Depending on the value of the slope or gradient if its the same then they are parallel if its a reciprocal then they are perpendicular.
How can we tell if two lines are parallel perpendicular or neither just from their equations?
If the slope of the equations are the same then they are parallel If the slope of the equations are minus reciprocal then they are perpendicular If the slope of the equations are different then they are neither
When 2 lines have slopes that are negative reciprocals of one another the graph of the equations are?
of mutually perpendicular lines.
Determine whether the graphs of the equations are parallelperpendicular or neither?
Base on the slope of two linear equations (form: y = mx+b, where slope is m): - If slopes are equal, the 2 graphs are parallel - If the product of two slopes equals to -1, the 2 graphs are perpendicular. If none of the above, then the 2 graphs are neither parallel nor perpendicular.
What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?
If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.
What equations describes a line that is perpendicular to 2x plus 9y equals 9?
Any one of them that has a slope of 9/2 or 4.5
Are perpendicular lines considered nonlinear?
No, two lines perpendicular to each other are wriiten as two separate equations. Both are linear.
Is y equals -4x plus 1 perpendicular?
It is perpendicular to a family of other linear equations: of the form 4y = x + c
If a system of linear equations has exactly one solution then the two lines are what?
perpendicular
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
What is the perpendicular distance from the point 4 -2 to the line 2x -y -5 equals 0 showing key stages of work?
Points: (4, -2) Equation: 2x-y-5 = 0 Perpendicular equation: x+2y = 0 Equations intersect at: (2, -1) Perpendicular distance is the square root of: (2-4)2+(-1--2)2 = 5 Distance = square root of 5
