Unanswerable. You need to specify the core size and material.
Using two 10 AWG wires with a diameter of 2.6 mm each, the voltage drop over 1500 metres would be less than 1 volt.
There is insufficient information in the question to answer it. You did not provide the size (gauge) of the cable. Please restate the question.
To answer this question the voltage of the genset is needed.
It depends on the material of the cable (aluminum or copper) and the gauge of the cable. (Thickness). And on the current you intend it to carry.
The answer is different depending on the supply voltage because the allowable volt drop is a percentage of the supply voltage.
With a constant voltage and increase in wire length will increase the end to end resistance and therefore the current will decrease.
The correct size of cable depends on the length of the cable run, as well as the voltage and current. Another consideration is what voltage loss is acceptable ? Safest answer would be to use a cable sizing table or online tool: http://www.solar-wind.co.uk/cable-sizing-DC-cables.html Hope that helps. G.
Need to know the voltage to give you a good answer.
Basic Telephony cable is manufactured with a built in capacitance of 0.084uF (microfarads) per mile on 22-24AWG (for example) wire. Basic cable length can be estimated with a voltmeter. Messuring the amount of voltage discharged when placing the wire to ground, discharging the stored voltage in the wire.
If the voltage is supplying any current through the cable, i.e. if there is any 'load' at the end, then the voltage will drop through the cable.
It will decrease the voltage drop.
The formula for a simple DC voltage drop across a cable is:VDrop = Vmeasured at the input of cable - Vmeasured at the output of cableThis formula may seem simplistic however keep in mind that the sensitivity, accuracy and resolution of measuring instrument instrument is what is really important.If you know the DC current flowing through the cable and the impedance of the cable then you can use Ohm's law. Vdrop = I R where Vdrop is the voltage drop across the cable in volts I is the current flowing through the cable in amperes R is the resistance of the cable in ohms.ADDITIONALCalculation of the voltage drop is given by the formula belowVoltage Drop (Volt) = [(mV/Am)/1000] * I * lWhere mV/Am = millivolt drop per meter per ampere of the cable(this information is given in the table based on IEE Wiring Regulation)I = Current in the cable (in Ampere)l = Distance of cable (in Metre)See related links below
Voltage Grade of cables specifies the safe voltages which the insulation of the cable can withstand.