Ohm's law states that I = V/R, where I is current in amperes, V is difference potential in volts, and R is resistance in ohms. If I goes up, by relation, either V increases or R drops or both occur. Correspondingly, R = V/I, so if V stays static and I increases, R must decrease.?æ
No. Ohm's law says that V=IR where V is the voltage, I is the current, and R is the resistance. If you look at the equation, you will notice that if R goes up, V goes up, too.
A negative resistance region is where the current goes up while the voltage goes down, or vice versa. This is a characteristic of the esaki or tunnel diode, when it is in its tunnel region.
The higher the resistance the dimmer the light will become. The voltage drop (current) is proportional to the resistance as seen in the equation V=IR, since voltage remains the same throughout a series circuit if the equivalent resistance goes up the amount of current reaching the lightbulb must go down to equal the voltage thus creating a dimmer lightbulb.
Half that, or 2 amps. The basic rule in circuits is that voltage (E) equals current (I) times resistance (R). Here's how that expression of Ohm's law looks: E= I x R That means that current equals voltage divided by resistance, as is shown here: I = E / R This expression says that resistance is inversely proportional to current (with voltage staying the same). Further, if resistance goes up, current goes down. If resistance doubles (goes up by a factor of 2), which it does in the case specified in the question, then current is cut in half (goes down by a factor of 2). Half of 4 amps is 2 amps, and that's where the answer came from.
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
Yes. When the voltage drops and the power requirement (watts) stays the same, the amperage goes up.
Ohms' law says if voltage stays constant resistance controls the current flow. Resistance goes up, current goes down. E/I*R.
Current is inversely proportional to the resistance of the circuit. Resistance goes up, current goes down. Resistance goes down, current goes up.
A negative resistance region is where the current goes up while the voltage goes down, or vice versa. This is a characteristic of the esaki or tunnel diode, when it is in its tunnel region.
v = i*RIf i goes down then R must go up (assuming v remains the same).AnwerCompletely impractical question. Resistance is not directly affected by voltage or current, so what you describe won't happen!
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It varies. On some items resistance goes up, some it goes down when temperature goes up.
The higher the resistance the dimmer the light will become. The voltage drop (current) is proportional to the resistance as seen in the equation V=IR, since voltage remains the same throughout a series circuit if the equivalent resistance goes up the amount of current reaching the lightbulb must go down to equal the voltage thus creating a dimmer lightbulb.
Ohms Law: V = IR (or equivalently, I = V/R) if voltage is held constant, then when resistance goes up, current goes down, and vice-versa. Say for instance, the voltage is 10 Volts, and resistance is 5 Ohms. That means the current is 2 Amps. (2 = 10/5) If the resistance is raised to 10 Ohms, then the current drops to 1 Amp. (10 = 10/1)
Half that, or 2 amps. The basic rule in circuits is that voltage (E) equals current (I) times resistance (R). Here's how that expression of Ohm's law looks: E= I x R That means that current equals voltage divided by resistance, as is shown here: I = E / R This expression says that resistance is inversely proportional to current (with voltage staying the same). Further, if resistance goes up, current goes down. If resistance doubles (goes up by a factor of 2), which it does in the case specified in the question, then current is cut in half (goes down by a factor of 2). Half of 4 amps is 2 amps, and that's where the answer came from.
Voltage is the electrical pressure in a circuitAmperes (amps) are the measure of electrical current in a circuitOhms are the measurements of resistance in a circuitCurrent is essentially how fast electrons are moving in a circuitResistance is what impedes the electrical current, and can be found in the wire or various loads in a circuitHope this helps!
The potential difference (voltage) between the ends of the branch, and the resistance of the branch. In a simple parallel circuit, the voltage is usually the full power supply, so the main thing to note is that none of the other parallel branches has any influence on the current through the parallel branch of interest.
Just as the name of the component implies, electrical current gets resisted and therefore it diminishes unless an equally, larger voltage difference in that section of the circuit is applied. V=IR Current is inversely proportional to Resistance (when one goes UP, the other goes DOWN) Voltage is directly proportional to Resistance