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P-Hydroxyacetophenone is very polar compared to o-Hydroxyacetophenone. Because polar compounds have stronger dipole-dipole interactions, they require a higher output of kinetic energy (temperature) in order to break (melt).

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βˆ™ 15y ago
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βˆ™ 12y ago

Weaker hydrogen bonding means less energy needs to be present to liberate it form the solid state. Also, don't ask Ochem questions here, people give you stupid answers.

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Q: O-Hydroxyacetophenone has a melting point of 4-6 degrees celsius while p-Hydroxyacetophenone has a melting point of 109-111 degrees Celsius please explain the sizable difference in the melting points?
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