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Decoder is the system which is used to decode or translate the code and make the message again readable. Both encoder and decoder are used where encoding language is applied. For example, if a word TRANSLATION is encoded then it can be written in various forms like NOITALSNART.
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What is the difference between the Intel 8085 and the Intel 8086?
The Intel 8085 is an 8 bit microprocessor created in 1977.The Intel 8086 is a 16 bit microprocessor created in 1978. The 8086 was the first chip to start the x86 architecture family.8085 contains 16-bit address bus and 8-bit data bus8086 contains 20-bit address bus and 16-bit data bus..In 8085 the clock speed is 3MHZwhere as in 8086 the clock speed is 5MHZ.there are two differences btw 8085&80861. 8086 has 6 byte queue but 8085 has 4 byte queue2. 8086 has 16 bit data bus where as 8085 has 8 bit data bus
Impliment 8 into 256 decoder using decoder circuit?
8:256 decoder circuit can be implemented by using 4:16 decoder circuit
The 16 bit microprocessor means that it has?
8 bit ALU and most of data processing registers will be 8 bit
What are operands?
Every instruction contains to parts: operation code[opcode],and operand. The first part of an instruction which specifies the task to be performed by the computer is called opcode. The second part of the instruction is the data to be operated on.,and it is called operand. The operand[or data]given in the instruction may be in various forms such as 8-bit or 16-bit data, 8-bit or 16-bit address, internal register or a register or memory location.
How many 3-to-8 line decoders with an enable input are needed to construct a 6-64?
You need 9 3-to-8 decoders. 8 decoders for selecting one of 64 lines. 1 decoder for enabling 1 decoder out of 8 decoder.
How does 8086 determine wheather instruction is 8 bit or 16 bit?
based on the size of the data bus they determine whether it is a 8 bit or 16 bit . here in 8086 it has 16 bit data bus hence it is called as 16 bit microprocessor
How many times can a 32-bit bus can handle versus the data bits as an 8-bit bus?
Lets put this one into a very tangible form. 8-Bit Bus: To process the text string "ABBA" an 8 bit bus will send the data like this(I'm using ABBA because its a band name and its very easy to write in binary): Instruction #1 [01000001] Instruction #2 [01000010] Instruction #3 [01000010] Instruction #4 [01000001] A 32-bit bus does lit like this: Instruction #1 [01000001];[01000010];[01000010];[01000001] At the most elemental scale, this would make a 32-bit bus 4 times faster than a 8-bit bus at the same frequency. More goes into it than this, however, and real-world numbers are never an exact representation of theoretical performance differences.
How do you draw the timing diagram for instruction INX H?
INX H instruction requires 1 machine cycle having 6 T-states because 8-bit instruction operate on 16 bit data (HL) completed in 6 T-states.
According to word size how many instruction in 8085?
The 8085 is an 8 bit processor, so its word length is 8 bits.
What Buffer register saves the instruction?
It is employed to hold temporarily the right hand instruction from a word in memory.. For example, The IAS machine's basic unit of information was a 40-bit, so that two instructions could be stored in each 40-bit memory location. Each instruction consisted of an 8-bit {operation code} and a 12-bit address. Hence the IBR (Instruction Buffer Register) is used to temporarily hold Right hand instruction for the next use.
What is instruction buffer register?
It is employed to hold temporarily the right hand instruction from a word in memory.. For example, The IAS machine's basic unit of information was a 40-bit, so that two instructions could be stored in each 40-bit memory location. Each instruction consisted of an 8-bit {operation code} and a 12-bit address. Hence the IBR (Instruction Buffer Register) is used to temporarily hold Right hand instruction for the next use.
How does the microprocessor work?
Suppose we give a 8-bit instruction ADD B to the microprocessor then this instruction is not at all understood by microprocessor as it only accepts binary inputs so first of all it stores the instruction in the INSTRUCTION REGISTOR then it decodes this instruction ADD B to its suitable binary code 80H in the INSTRUCTION DECODER.. after converting to 80H then the microprocessor understands that .. yes i have to add the content of the resistor B with that of A(accumulator) and store the result in the accumulator A this is a small example how microprocessor operates facing the instructions
