8 bit ALU and most of data processing registers will be 8 bit
Two bytes of 8 bits, per instruction.
Because it is an 8-bit microprocessor.
The 16 bit Microprocessor means that it has?
it is a 16 bit microprocessor & it has 40 pin .
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
16 bit addition
Because the processor is a 16 bit processor, and 64k is what you can address with a 16 bit processor.
The 8085 was replaced with the 8086/8088. As such, there is no 16 bit version of the 8085.
HL is a register pair used to store 16 bit of data in 8085 microprocessor.
Even though the 8085 is an 8 bit microprocessor, it can address 64K memory, because it has a 16 bit address bus.
the pin configuration of a processor means that the diagramatic representation of block diagram of processor representing various pins and the function of that pins
Because that's how Intel designed it. The 8085 is an 8-bit computer operating on a 16-bit address space.
The 8086/8088 microprocessor family is a 16 bit microprocessor. The 8086 implementation also has a 16 bit data bus, but the 8088 implementation has an 8 bit data bus, comparable to the 8085. The 8088 implementation was intended as a logical upgrade from the 8085, while keeping the complexity of the system on an equal footing as the 8085.