Silver fluoride is more ionic in nature than silver iodide. Being more ionic it is more soluble than silver iodide which is more covalent. The reason is that the fluorine ion is less polarizable than the larger iodide ion. This is an example of Fajans rules.
All silver halides are insoluble. It has to do with the relatively low electronegativity difference between silver and bromine; also a concept called "Fajan's Rule," which says that silver's ionic radius is similar in size to halide ionic radii, meaning they can "snuggle up close" to each other, rendering them difficult to dissociate in water.
The solubility largely depends on the amount of energy which can be released as the silver and the halide ion become hydrated and whether this (together with entropy effects) is sufficient to overcome the energy required to break up the crystal lattice. The hydration energy of fluoride ions is much greater than that of iodide ions, because the fluoride ions are much smaller, and therefore have a much higher charge density than do iodide ions. This means that the polar water molecules are more strongly attracted to the fluoride ions. http://www.chembook.co.uk/chap16.htm
No, Ag, Hg2 and Pb in the same compound as halogens(halide Ions are NOT soluble
Potassium chloride (KCl) is soluble in water.
Yes, it is insoluble.
AgBr is the chemical formula of silver bromide.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Silver Bromide
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
AgBr
Silver bromide (AgBr), a soft, pale-yellow, water insoluble salt
Some examples of insoluble bromide compounds include silver bromide (AgBr), lead(II) bromide (PbBr2), and mercury(I) bromide (Hg2Br2). These compounds do not dissolve easily in water and form solid precipitates when bromide ions are combined with the corresponding metal ions.
AgBr is the chemical formula of silver bromide.
AgBr is the chemical formula (not symbol) of silver bromide.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Silver Bromide
Element
Compound
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
Silver Bromide
AgBr
Its yellow in colour