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Silver fluoride is more ionic in nature than silver iodide. Being more ionic it is more soluble than silver iodide which is more covalent. The reason is that the fluorine ion is less polarizable than the larger iodide ion. This is an example of Fajans rules.
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∙ 11y ago
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∙ 8y agoAll silver halides are insoluble. It has to do with the relatively low electronegativity difference between silver and bromine; also a concept called "Fajan's Rule," which says that silver's ionic radius is similar in size to halide ionic radii, meaning they can "snuggle up close" to each other, rendering them difficult to dissociate in water.
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∙ 7y agoThe solubility largely depends on the amount of energy which can be released as the silver and the halide ion become hydrated and whether this (together with entropy effects) is sufficient to overcome the energy required to break up the crystal lattice. The hydration energy of fluoride ions is much greater than that of iodide ions, because the fluoride ions are much smaller, and therefore have a much higher charge density than do iodide ions. This means that the polar water molecules are more strongly attracted to the fluoride ions. http://www.chembook.co.uk/chap16.htm
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∙ 13y agoNo, Ag, Hg2 and Pb in the same compound as halogens(halide Ions are NOT soluble
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∙ 10y agoPotassium chloride (KCl) is soluble in water.
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∙ 11y agoYes, it is insoluble.
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What is the chemical formula AgBr?
AgBr is the chemical formula of silver bromide.
What is the mass of NaBr that will be produced from 42.7 g of AgbR?
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
What is AgBr?
Silver Bromide
What is compound formula for silver bromide?
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
What is the chemical formula for silver bromide?
AgBr
What is the chemical formula for silver 1 and bromine?
Silver bromide (AgBr), a soft, pale-yellow, water insoluble salt
What are insoluble bromide compounds?
Some examples of insoluble bromide compounds include silver bromide (AgBr), lead(II) bromide (PbBr2), and mercury(I) bromide (Hg2Br2). These compounds do not dissolve easily in water and form solid precipitates when bromide ions are combined with the corresponding metal ions.
What is the chemical formula AgBr?
AgBr is the chemical formula of silver bromide.
What does the symbol AgBr stand for in chemistry?
AgBr is the chemical formula (not symbol) of silver bromide.
What is the mass of NaBr that will be produced from 42.7 g of AgbR?
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
What is AgBr?
Silver Bromide
Is AgBr a element or a compound?
Element
Is AgBr an element or a compound?
Compound
What is compound formula for silver bromide?
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
What is the appropriate name for AgBr?
Silver Bromide
What is the chemical formula for silver bromide?
AgBr
What color is AgBr as a precipitate?
Its yellow in colour
