Why is AgBr insoluble?

Answer 1

Silver fluoride is more ionic in nature than silver iodide. Being more ionic it is more soluble than silver iodide which is more covalent. The reason is that the fluorine ion is less polarizable than the larger iodide ion. This is an example of Fajans rules.

Answer 2

All silver halides are insoluble. It has to do with the relatively low electronegativity difference between silver and bromine; also a concept called "Fajan's Rule," which says that silver's ionic radius is similar in size to halide ionic radii, meaning they can "snuggle up close" to each other, rendering them difficult to dissociate in water.

Answer 3

The solubility largely depends on the amount of energy which can be released as the silver and the halide ion become hydrated and whether this (together with entropy effects) is sufficient to overcome the energy required to break up the crystal lattice. The hydration energy of fluoride ions is much greater than that of iodide ions, because the fluoride ions are much smaller, and therefore have a much higher charge density than do iodide ions. This means that the polar water molecules are more strongly attracted to the fluoride ions. http://www.chembook.co.uk/chap16.htm

Answer 4

Silver bromide (AgBr) is insoluble in water because of the strong ionic bonds between silver ions (Ag+) and bromide ions (Br-). These bonds prevent the individual ions from dissociating and dissolving in water. As a result, AgBr remains as a solid precipitate in water.

Answer 5

No, Ag, Hg2 and Pb in the same compound as halogens(halide Ions are NOT soluble

Answer 6

Potassium chloride (KCl) is soluble in water.

Answer 7

Yes, it is insoluble.