Oh yes, silver bromide is indeed a solid.
The balanced chemical equation for the reaction between solid silver hydroxide (AgOH) and hydrobromic acid (HBr) is: 2 AgOH (s) + 2 HBr (aq) → 2 H2O (l) + 2 AgBr (s) This equation shows that two moles of silver hydroxide react with two moles of hydrobromic acid to produce two moles of water and two moles of silver bromide.
Образуется растворимое комплексное соединение: AgBr + 2 NH4OH -----> [Ag(NH3)2]+ + Cl- + 2 H2O.
AgBr is a compound composed of silver (Ag) and bromine (Br) elements.
The compound AgBr is called silver bromide, which is a white solid commonly used in photographic films and papers due to its light sensitivity.
A sample of 0.3220 g of an ionic compound containing the bromide ion Br is dissolved in water and treated with an excess of AgNO3 If the mass of the AgBr precipitate that forms is 0.6964 g then bromide=0.3220g and AgBr precipitate=0.6964.
AgBr stands for silver bromide, which is a chemical compound composed of silver and bromine. It is commonly used in black and white photography as a light-sensitive material to capture images on film. AgBr is a pale yellow or white solid that is insoluble in water.
The balanced chemical equation for the reaction between solid silver hydroxide (AgOH) and hydrobromic acid (HBr) is: 2 AgOH (s) + 2 HBr (aq) → 2 H2O (l) + 2 AgBr (s) This equation shows that two moles of silver hydroxide react with two moles of hydrobromic acid to produce two moles of water and two moles of silver bromide.
AgBr is the chemical formula of silver bromide.
To find the mass of AgBr formed, first calculate the moles of AgNO3 in 35.5 mL of 0.184 M solution. Then, use the mole ratio from the balanced chemical equation between AgNO3 and AgBr to find the moles of AgBr formed. Finally, multiply the moles of AgBr by its molar mass to get the mass. Note that since HBr is in excess, AgNO3 will be the limiting reagent.
The chemical formula for silver bromide is AgBr.
AgBr is the chemical formula (not symbol) of silver bromide.
Образуется растворимое комплексное соединение: AgBr + 2 NH4OH -----> [Ag(NH3)2]+ + Cl- + 2 H2O.
Silver bromide (AgBr) is a light yellowish precipitate.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Silver bromide.
AgBr is a compound composed of silver (Ag) and bromine (Br) elements.
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.