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The Angular Momentum Quantum number L, defines how many types of orbitals can exist.

For a particular Quantum Level n, L is defined as any integer from 0 to L = n-1.

For example, for the energy level n = we must have, L = 0 or 1.

L=0 relates to the s-orbital

L=1 relates to the p-orbital

L=2 would relate to the d-orbital, but we can see here that for n=2, L cannot = 2

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Q: Why there is no possibility of 2d and 3f orbitals?
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Which of these orbital designations are invalid a. 4s b. 2d c. 3f d. 3p?

The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.


Which of the orbital designation are invalid 4s 3f 2d 3d?

3f ( 3 only has the d orbital final ) and 2d ( 2p is the final orbital on the 2 level )


Which of the orbitals contains quantum number combinations that are not possible?

3f


What combinations of n and i represent real orbitals and which do not exist?

3f


Which of the following atomic orbital designations are incorrect 7f 6p 2d 3f?

2d is incorrect


What orbitals is not possible 3p 4s 2d 5f?

2d Only s and p in the 2 level


Can 3f orbital be exist?

no because f orbitals are not energetically available until the n=4 quantum state


How much electrons can be in a 3f orbital?

There can be a maximum of 14 electrons in any "f" orbital. However, the 3f orbital does not exist. f orbitals are only found in quantum energy level 4 and above.


What is an invalid orbital designation 4p 3s 2d 5f?

2d is invalid. Only s and p orbitals in 2nd energy level


Why 2d3d orbitals can not exist?

3d orbitals do exist and 2d orbitals dont exist because of the pauli exclusion principle which says only 6 electrons can exist in the 2nd shell, and you need at least 7 to get a d subshell


What is the hardest elimentry dressage test?

the 3F then to medium also prelim it goes: 1A 1B 1C 1D 1E 1F Novice: 2A 2B 2C 2D 2E 2F AND ELIMENTRY: 3A 3B 3C 3D 3E 3F


-3f - 14 equals 1?

-3f - 14 = 1 -3f = 1+14 -3f = 15 f = -5