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Why you use an array of pointer to pointer?

Updated: 8/16/2019
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15y ago

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because u freakin can

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Q: Why you use an array of pointer to pointer?
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What is a pointer in the array?

A pointer into an array of elements of type E is a pointer to a single element of type E:typedef ..... E;E array[123];E* const pointer = &array[18]; // points to the 19th element inside 'array'An array of pointers is an array whose elements are pointers:typedef .... E;E* array[123];E** const pointer = &array[18]; // points to the 19th pointer within 'array'Referencing the name of the array variable without use of the index operator itself is a constant pointer to its first element. Therefore, the following if-clause is always true:typedef .... E;E array[123];if (array &array[N]) { // ALWAYS true ...}


Passing an array name to a pointer assigns the first memory location of the array to the pointer variable?

Yes, passing an array name to a pointer assigns the first memory location of the array to the pointer variable. An array name is the same as a pointer to the first location of the array, with the exception that an array name is a r-value, while a pointer is an l-value.


Which two pointer does not increment or decrement in arithmetic array?

constant pointer and character pointer


Why can't we increment an array like a pointer?

once we initialize the array variable, the pointer points base address only & it's fixed and constant pointer


When does an array behave a pointer?

An array behaves like a pointer when you use its name in an expression without the brackets.int a[10]; /* a array of 10 ints */int *b = a; /* a reference to a as a pointer, making b like a */int c = *(a+3); /* a reference to a[3] using pointer semantics */myfunc(a); /* pass a's address, a pointer to myfunc */Note very carefully that, while an array name and a pointer can almost always be interchanged in context, the are not the same, in that a pointer is an l-value, such as b, above, and can be assigned, whereas a is an r-value and can only be referenced, such as in the same statement, the second statement. Also, an array name does not take up memory, while a pointer does.


Use of double pointer?

A double pointer has two basic meanings. One is ofa pointer to a pointer, where changing the value ofdouble pointer will result in the original pointer being changed. Another is that of a two-dimentional array, such as a matrix, or a list of char* (e.g. in main when you use argv).


How do you return an array from function?

By returning a pointer to the first element of the array.


How do you print array variable without using array subscripts?

Well the most prolific answer to this query would be the use of pointers.Use a pointer and allocate it to the array of interest and start printing.


Delete memory release operator in c plus plus?

You can't physically delete memory, you can only delete a pointer to allocated memory, which subsequently releases the memory back to the system. The operator is delete, passing the pointer as the operand. If the pointer points to an array, then you must also use the index operator [] in front of the pointer name.int main(){// pointer to an int type with value 100int* ptr_int = new int(100);// ... use pointer ...// release the integerdelete ptr_int;// pointer to an array 100 int types (with undefined values)int* ptr_int_array = new int[100];// ... use array ...// release the arraydelete [] ptr_int_array;return(0);}


Searching array element by using pointer in c plus plus?

The name of an array can be looked as a pointer of this array,and it points to the local memory address of the first element.So we can gave the address to a pointer.The flow is an easy example to show hou to use a pointer to print an array.#include "iostream.h"void main(){char a[]="abcdefgh";char *b=a;//afor(int i=0;i


How do you convert from array notation to pointer notation?

In the C and C++ languages the array notation arr[i] is completely equivalent to the pointer notation *(arr + i).


What is the relationship between an array and a pointer?

All variable names are an alias for the value stored at the memory address allocated to them. To get the memory address itself, you must use the address of operator (&). The value returned from this can then be stored in a pointer variable.Arrays are different. The array name is an alias for the start address of the array, thus you do not need the address ofoperator to obtain the memory address (although you can if you want to). This means that when you pass an array name to a function, you pass the memory address of the array rather than passing the array itself (which would require the entire array to be copied, which is a highly inefficient way to pass an array). In essence, the array is passed by reference rather than by value.Consider the following code. This shows how a primitive variable name differs from the name of an array of primitive variables. The final portion shows how a pointer can be used to achieve the same results you got by accessing the array elements directly from the array name itself. This is in fact how the compiler implements arrays, using pointers, but there's no need to do this in your code. Accessing array elements directly by their index is a programming convenience.#include using namespace std;int main(){int i = 10;cout