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A switch is used to connect or disconnect a load from a source of voltage. If you take the input and connect directly to the output the result is that the connected device is always on.

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13y ago
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Q: Will a circuit work with the switch and will it work if you take the switch out of the circuit?
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Related questions

What position does the switch have to be in for a circuit to work?

The switch would be open.


What does a switch do in its circuit?

A switch allows the circuit to have a break in it therefor making it not work. It stops the flow of electrons.


Is a switch needed to make a circuit work?

Not always. Depends on the circuit.


Will a circuit work without a switch?

Yes a circuit will work without a switch but the only problem will be is that electricity will be wasted and there will be no device to stop the flow of current


An appliance does not work at all when plug it in and turn the switch what happen to the appliance circuit is?

If an appliance does not work at all when you plug it in and turn the switch on the appliance circuit is not on.


If an appliance does not work at all when you plug it in and turn the switch on the appliance circuit is what?

The appliance's circuit is open.


Can series circuits work when a switch is open?

No. Since the switch is in series with the circuit, opening it blocks the current flow through the circuit, turning it off.


When you flip a switch to turn on the light you?

Either close the circuit, or complete the circuit, should work here.


Why a circuit will not work if the switch is off?

Current flow path is open.


Why bulb does not work when fitted in a circuit with switch?

because you are switch the hot leg, so it can be turn on an off.


How does a brake light switch work on a Peterbilt?

There's continuous power supplied to the circuit. When the switch contacts, it closes the circuit and allows the power to go to the brake lights.


How do light swithes turn on?

Basically, when you click that switch, it completes a circuit for the electricity to flow. If the circuit is not completed in any part, the circuit will not work at all