Can you please tell me the c program to print the following pattern... 1 123 12345 1234567?

Answer 1

This was checked for C++ using VS2008.

#include

using std::cin;

using std::cout;

using std::endl;

int main()

{

cout << endl << "Enter of digits in the last number of the patter "

<< endl << "(should be odd number, if you enter even number N," << endl << "the answer will have N - 1 digits in the last number): ";

int numElem = 0;

cin >> numElem;

cout << endl << "Pattern:" << endl;

for (int i = 1; i <= numElem; i += 2)

{

for (int j = 1; j <= i; j++)

{

cout << j;

}

cout << endl;

}

system("PAUSE");

return 0;

}

For just C you might want to use something like (not tested):

#include

int main()

{

cout << endl << "Enter of digits in the last number of the patter "

<< endl << "(should be odd number, if you enter even number N,"

<< endl << "the answer will have N - 1 digits in the last number): ";

int numElem = 0;

cin >> numElem;

cout << endl << "Pattern:" << endl;

for (int i = 1; i <= numElem; i += 2)

{

for (int j = 1; j <= i; j++)

{

cout << j;

}

cout << endl;

}

system("PAUSE");

return 0;

}

Answer 2

class logic

{

public static void main(String args[])

{

int a,b;

for(a=1;a<=5;a++)

{

for(b=1;b<=a;b++)

System.out.print(b+" ");

}

}

}

Answer 3

System.out.println("1234 123 12 1 12 123 1234");

Or write two nested loops for the descending sequence, and then again two nested loops for the ascending sequence, printing one digit at a time, and using print() instead of println().

Answer 4

public class apples {

public static void main(String argc[]) {

System.out.println("12321");

}

}

Answer 5

for (int i=0; i<5; ++i) { System.out.print (i+1);

System.out.print (' ');

System.out.print (5-i);

System.out.print (' ');

}

Answer 6

Use a nested loop:

int x, y;

for (x=1; x<=5; ++x)

for (y=1; y<=x; ++y)

System.out.print(y);