#include #include void main() { char string[50]; int vowel=0,consonant=0; cout<<"Enter the string"; cin.getline(string,50); for(int i=0;string[i]!='\0';i++) { switch (string[i]) { case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':vowel++; continue; } if (string[i]!=' ') consonant++; } cout<<"No of vowels="<<<"\nNo of consonants="<
A simple way to do this, whatever the language used, is to step through the characters in the string one by one and compare them with a previously established set of vowels, adding one to a count value every time a character matches one of the vowels. The count value at the end will be the number of vowels.
Remember to define the set of vowels and the count value and to check for an empty string and for the end of the string.
Here are some examples of programs that count the number of vowels in a string in different programming languages. C++ Example 1void main() {char *str; char a[]="aeiouAEIOU"; int i,j,count=0; clrscr(); printf("\nEnter the string\n"); gets(str); for(i=0;str[i]!='\0';i++) { for(j=0;a[j]!='\0';j++) if(a[j] == str[i] { count++; break;
}
printf("\nNo. of vowels = %d",count); getch();
}
} C++ Example 2#include
#include
int main (void) {char s[100];
int i,c=0;
clrscr();
printf("\n Enter a string");
scanf("%s",s); for(i=0;s[i]!='\0';i++)
{
if (s[i]=='a's[i]=='A's[i]=='e's[i]=='E's[i]=='i's[i]=='I's[i]=='o's[i]=='O's[i]=='u's[i]=='U') { c++;
}
}
printf("\nThe no. of vowels in the given string is=%d",c);
getch();
return 0;
}
} Javascript Exampleb = prompt("Enter the String","");
c=0;
for (i=0;i<b.length;i++) {if ("aeiou".indexOf(b.substr(i,1).toLowerCase())!=-1){ c++;
}
}
alert("No. of Vowels: "+c); PHP Example$vowels = array('a','e','i','o','u');
$string = 'An example string';
$length = strlen($string);
$count = 0;
for ($i = 0; $i !== $length; $i++;) {if (array_search($length[$i], $vowels)) { $count++;
}
}
echo 'There are (' . $count . ') vowels in the string (' . $string . ').';
Another way to do this would be through the use of RegExes/Pattern matching
Javascript Example:
str="A string for use of testing";
count= str.match(/[aeiou]/gi).length;
console.log("There are "+count+" vowels");
Java Example:
import java.util.regex.*;
public static void main(String[] args){
String str= "A string for use of testing";
Matcher m= Pattern.compile("(?i)[aeiou]").matcher(str);
int count= 0;
while (m.find()){
count+= m.end()-m.start();
}
System.out.println("There are "+count+" vowels");
}
#include<stdio.h>
#include<conio.h>
int main (void)
{
char s[100];
int i,c=0;
clrscr();
printf("\n Enter a string");
scanf("%s",s);
for(i=0;s[i]!='\0';i++)
{
if(s[i]=='a's[i]=='A's[i]=='e's[i]=='E's[i]=='i's[i]=='I's[i]=='o's[i]=='O's[i]=='u's[i]=='U')
c++;
}
printf("\n the nos. of vowels in the given string is=%d",c);
getch();
return 0;
}
//testing code
//note that a space character should be neither a vowel, nor a consonant
string s = "This is a test";
Console.WriteLine("Source string: {0}", s);
Console.WriteLine("# of Vowels: {0}",
GetCount(s, "aeiou"));
Console.WriteLine("# of Consonants: {0}",
GetCount(s, "bcdfghjklmnpqrstvwxyz"));
// helpers
// get number of characters in source that are in charactersToMatch
public int GetCount(string source, string charactersToMatch)
{
char[] target = charactersToMatch.ToCharArray();
int count = 0;
foreach (char c in source.ToLower()) {
if (IsMatch(c, target)) count++;
}
return count;
}
//returns true if c is one of patterns, false otherwise
public bool IsMatch(char c, char[] patterns)
{
foreach (char p in patterns) {
if (c == p) return true;
}
return false;
}
#include<iostream.h>
#include<conio.h>
main()
{
char str[10];
int v=0;
cout<<"Please enter a string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++)
{
if(str[i]=='a'str[i]=='A'str[i]=='e'str[i]=='E'str[i]=='i'str[i]=='I'str[i]=='o'str[i]=='O'str[i]=='u'str[i]=='U')
v++;
}
cout<<" Number of Vowels are there.= "<<v;
getch();
}
#include
int str_vowels(char* s)
{
int numbers = 0;
int n = 0;
while(s[n]!='\0')
{
if(s[n]=='a's[n]=='e's[n]=='i's[n]=='o's[n]=='u')
{
numbers++;
}
n++;
}
return numbers;
}
int main()
{
char s[1024];
printf("Enter a string:");
scanf("%s", s);
printf("The numbers of vowels present in the string is %d\n", str_vowels(s));
return 0;
}
For PHP:
<?php
$string="umbrella";
echo "There are ".preg_match_all('/[aeiou]/',$string,$matches)." vowels in string "."<strong>".$string."</strong>";
?>
To find vowels present in string, you must first scan the string for values. Scan each letter on string (as characters) and analyze if they are vowels or not. You can use for loop (since loops are best used with arrays) and conditional statements to scan and analyze each letter. If and Else statements can be handy. But you can also use switch. Also, you will need to use <string.h> in extracting and analyzing words.
char strword[7] = "create"
length = strlen(strword);
for (ctr = 0; ctr < length; ctr++) {
if (strword[ctr] 'u') {
printf ("%c <-- This letter is a vowel\n", strword[ctr]);
}
}
In most cases you use C++, but for your general question, you use pseudocode.
Yes, you can, but you have to put codes of all vowels in your program.
#include<iostream> #include<fstream> #include<string> int main() { size_t count=0; std::string vowels ("aeiouAEIOU"); std::ifstream ifs; ifs.open ("test.txt", std::ios::in); if (ifs.bad()) { ifs.close(); std::cerr << "Invalid input file.\n" << std::endl; return; } while (!ifs.eof()) { char c = ifs.get(); if ((c>='a' && c<='z') (c>='A' && c<='Z')) if (vowels.find (c) != vowels.npos) ++count; } ifs.close(); std::cout << "The file has " << count << " non-vowels.\n" << std::endl; }
You need to scan through the string and keep track of the vowelsoccurring. Here is a sample program:#include#includeint countVowels(char[] s){int count = 0, i;for( i=0; char[i] != '\0'; i++){switch(char[i]){case 'a':case 'e':case 'i':case 'u':case 'o': count++;break;}}return count;}int main(){char str[256];printf("Enter the string:\t");scanf("%s", str);printf("The number of vowels in the string are :%d\n", countVowels(str));return 0;}
That's easy to do!This script will get the POST data from an HTML form and check if it is a vowel.
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
flow chart
build an array of vowels then do a foreach on the array and then explode the string on the array value and the answer is -1 of the result
Here is an example of how you can find the vowels in a string using PHP: $str = "Hello World"; $vowels = preg_match_all('/[aeiou]/i', $str, $matches); echo "Vowels found: " . $vowels; This code snippet uses a regular expression to match all vowels (both uppercase and lowercase) in the string "Hello World" and counts how many vowels are found.
#include<iostream> #include<fstream> #include<string> int main() { size_t count=0; std::string vowels ("aeiouAEIOU"); std::ifstream ifs; ifs.open ("test.txt", std::ios::in); if (ifs.bad()) { ifs.close(); std::cerr << "Invalid input file.\n" << std::endl; return; } while (!ifs.eof()) { char c = ifs.get(); if ((c>='a' && c<='z') (c>='A' && c<='Z')) if (vowels.find (c) != vowels.npos) ++count; } ifs.close(); std::cout << "The file has " << count << " non-vowels.\n" << std::endl; }
You need to scan through the string and keep track of the vowelsoccurring. Here is a sample program:#include#includeint countVowels(char[] s){int count = 0, i;for( i=0; char[i] != '\0'; i++){switch(char[i]){case 'a':case 'e':case 'i':case 'u':case 'o': count++;break;}}return count;}int main(){char str[256];printf("Enter the string:\t");scanf("%s", str);printf("The number of vowels in the string are :%d\n", countVowels(str));return 0;}
That's easy to do!This script will get the POST data from an HTML form and check if it is a vowel.
There are 3 vowels in "hypothesis" (4 if you count the 'y').
suppose we have a string String s = "hello how are you..."; char arr[] = s.toCharArray(); for(i = 0; i < arr.length; i++) { if(arr[i] 'u') System.out.println(arr[i]); } that is it .I hope it works.If there is a better process let me know at :- "hello2.abhishek.pal@gmail.com"...
Read the characters one at a time, and write an "if" for each of the cases. In each case, if the condition is fulfilled, increment the corresponding counter variable.
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
substr(string, position [, count]) It extract substring starting from start and going for count characters. If count is not specified, the string is clipped from the start till the end
flow chart
There is no specific collective noun for the noun vowels, in which case a noun suitable for the situation can be use, for example a group of vowels, a string of vowels, a bunch of vowels, etc.