flow chart
#include<iostream> #include<fstream> #include<string> int main() { size_t count=0; std::string vowels ("aeiouAEIOU"); std::ifstream ifs; ifs.open ("test.txt", std::ios::in); if (ifs.bad()) { ifs.close(); std::cerr << "Invalid input file.\n" << std::endl; return; } while (!ifs.eof()) { char c = ifs.get(); if ((c>='a' && c<='z') (c>='A' && c<='Z')) if (vowels.find (c) != vowels.npos) ++count; } ifs.close(); std::cout << "The file has " << count << " non-vowels.\n" << std::endl; }
#include #include void main() { char string[50]; int vowel=0,consonant=0; cout<<"Enter the string"; cin.getline(string,50); for(int i=0;string[i]!='\0';i++) { switch (string[i]) { case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':vowel++; continue; } if (string[i]!=' ') consonant++; } cout<<"No of vowels="<<<"\nNo of consonants="<
clsinput" enter any string";a$f=Len(A$)d=1AA:b$= mid$(a$,d,1)d=d+1c=asc(b$)if c=101 or c=105 or c=970 or c=111 or c=117 thencnt= cnt+1end ifif d
#include "stdio.h" int main() { unsigned int number, count; printf("Enter the Number \t"); scanf("%d", &number); printf("The even numbers are: \n"); for(count = 0x01; (count < number && number!= 0x00)) { if(count%2) { }else { printf("%d\n", count); } count++; } return 0; }
You need to scan through the string and keep track of the vowelsoccurring. Here is a sample program:#include#includeint countVowels(char[] s){int count = 0, i;for( i=0; char[i] != '\0'; i++){switch(char[i]){case 'a':case 'e':case 'i':case 'u':case 'o': count++;break;}}return count;}int main(){char str[256];printf("Enter the string:\t");scanf("%s", str);printf("The number of vowels in the string are :%d\n", countVowels(str));return 0;}
There are 3 vowels in "hypothesis" (4 if you count the 'y').
2,three if you count Y
4: sen-say-shun-al. Generally, just count the number of times that single vowels or groups of vowels appear inside the word. There are exceptions e.g. words ending in es.
build an array of vowels then do a foreach on the array and then explode the string on the array value and the answer is -1 of the result
2 syllables......... Addition: Just count how many vowels the word has. So in this case the word "trapped" has two vowels....
what is the ratio of the numbers vowels to the number of consonants in the english alphabet
No, "photosynthesis" contains other vowels already. The only time when "y" would be considered a vowel is when there are no other vowels in the word.
one
what is the ratio of the numbers vowels to the number of consonants in the english alphabet
zero !
Two (e and e). If you count 'y' as a vowel, there's three.
The number 7/seven, it has two vowels and three consonants....... thats the answer I see best for your question........