fibbonacci starts out as 1,1,2,3,5,8,13,21,34....meaning 1 + 1 = 2, 2 +1 = 3, 3+2 = 5 and so on the solution in C++.
#include <iostream>
using namespace std;
int main()
{
short a = 1;
short b = 1;
short c = 2;
do
{
a = c + b;
cout << a << "\n";
b = a + c;
cout << b << "\n";
c = b + a;
cout << c << "\n";
}while (a && b && c != 34);
return 0;
}
in this i used short int because, i was only going to go up to 34 to keep things short an simple.
I then figured out in what order i would have to figure out my variables on paper. I assigned values to my variables to have a starting point then used a do-while to loop the program. I made sure that my varibles were all checked against 34 so it would have a break point and not run on forever.
Every computer language has different syntax, so writing a set program without knowing the language is infeasible. However, the general algorithm for generating a Fibonacci sequence is as follows. Input -> n; temp1 = 0; temp2 = 1; temp3 = 0; if (n = 0), output: temp1; else if (n = 1), output: temp2; else output: temp1; output: temp2; for loop (base: 0, check: n-1, base++) {temp3 = temp2 + temp1; output: temp3; temp2 = temp1; temp1 = temp3;}
// recursive method - very slow for larger numbers
unsigned long fib (unsigned long n) {
if (n 2) return 1;
return fib (n-1) + fib (n-2);
}
int main (int argc, char* argv[]) {
unsigned long n, f;
for (n = 1; n < 50; ++n) {
f = fib(n);
if (f > 100) break;
printf ("%lu %lu\n", n, f);
}
return 0;
}
#include<stdio.h>
void main()
{
int arr[12],n;
int a=0,b=1,c,i,j,flag=0;
arr[0]=a;arr[1]=b,i=2;
clrscr();
printf("\nEnter the values:");
scanf("%d",&n);
do
{
c=a+b;
arr[i++]=c;
a=b;
b=c;
} while(c<n);
printf("\nNon Fibnoacci series is:");
for(i=0;i<n;i++)
{
flag=0;
for(j=0;j<10;j++)
{
if(i==arr[j])
{
flag=0;
break;
}
else
flag=1;
}
if(flag==1)
{
printf("%d ",i);
}
}
getch();
}
function fib() { local x y z n; x=1; for n in `seq 1 $1` ; do z=$((x+y)); echo -e "$n\t:\t$z"; x=$y; y=$z; done; }
a=0
b=1
c=0
For i=0 to whaterveryouwant
print c
c=a+b
a=b
b=c
next i
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
write a program to print the series 1/12+1/22+.........+1/n2 ?
The Fibonacci sequence uses recursion to derive answers. It is defined as: F0 = 0 F1 = 1 Fn = F(n - 1) + F(n -2) To have this sequence printed by a php script use the following: function fibonacci($n) { if($n 1) return 1; //F1 else return fibonacci($n - 1) + fibonacci($n - 2); //Fn } This recursive function will print out the Fibonacci number for the integer n. To make it print out all the numbers in a particular set add this to your script. for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } So your final result would look like. <?php function fibonacci($n) { if($n 1) return 1; else return fibonacci($n - 1) + fibonacci($n - 2); } for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } ?>
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
If you have the series stored in an array, you loop through the array and print each array element in turn. Another possibility is to print out the numbers in the series as you generate them. In that case, you may not need to store anything (depending on the series, of course).
write a program to print the series 1/12+1/22+.........+1/n2 ?
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
The Fibonacci sequence uses recursion to derive answers. It is defined as: F0 = 0 F1 = 1 Fn = F(n - 1) + F(n -2) To have this sequence printed by a php script use the following: function fibonacci($n) { if($n 1) return 1; //F1 else return fibonacci($n - 1) + fibonacci($n - 2); //Fn } This recursive function will print out the Fibonacci number for the integer n. To make it print out all the numbers in a particular set add this to your script. for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } So your final result would look like. <?php function fibonacci($n) { if($n 1) return 1; else return fibonacci($n - 1) + fibonacci($n - 2); } for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } ?>
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
If you have the series stored in an array, you loop through the array and print each array element in turn. Another possibility is to print out the numbers in the series as you generate them. In that case, you may not need to store anything (depending on the series, of course).
write a program to print A to Z on screen in c?
CLS a = 0 b = 0 FOR i = 1 TO 10 IF a = 0 THEN f = 1 END IF PRINT f b = a a = f f = a + b NEXT i END from : Parth jani parthjani7@yahoo.com
echo 'print a pattern'
Q.1 Write a program to print first ten odd natural numbers. Q.2 Write a program to input a number. Print their table. Q.3 Write a function to print a factorial value.
to print the Fibonacci series until 100 you can take the input in d to make it run for whatever value you want void main(){ int a,b,c,d; a=0; b=1; c=1; d=100; while(c<d) { printf("%d\n",c); c=a+b; a=b; b=c; } }
10 print "That is not a question." 20 print "That is a command." 30 end
//WAP to print fibonacci series using do-while loop.? using System; class Fibonacci { public static void Main() { int a=1,b=1; int sum=0; Console.Write("Enter Limit:"); int n=Int32.Parse(Console.ReadLine()); Console.Write(a); Console.Write(b); do { sum=a+b; a=b; b=sum; Console.Write(sum); } while(sum<n); } } By-Vivek Kumar Keshari