A little more than one cubic yard of crushed rock is needed. (10 ft x 6 ft x 1/6 ft = 10 cu ft = 1 cu yd + 1 cu ft)
1.85 cubic yards...probably 25 bags or so
3 in = .25 ft 220 sq ft x .25 = 55 cubic ft 27 cubic ft = 1 cubic yd 55/27 = 2 cubic yds.
The answer depends on how deep the granite is meant to be.
630 cubic inches
160 cubic inches / (1/8 inches) = 160*8 = 1280 sq inches
1 (cubic yard) = 46 656 cubic inchesIf the depth is 2 inches then the area it will cover is 46656/2 square inches = 23,328 square inches. Convert 23,328 square inches to square yards23 328 (square inches) = 18 square yards
A cubic yard is 46,656 cubic inches. Spread to a thicknes of 5 inches, a cubic yard of concrete covers 9332.1 square inches, which is 64.8 square feet.
One "yard" of dirt (meaning one cubic yard) contains 46,656 cubic inches. Spread 8 inches thick this will cover 5832 square inches or 40.5 square feet.
Not sure what 2b is but crushed concrete with 1 1/2" rock will cover about 60 square feet. 15 tons ends up being around 12 cubic yards.
"4 inches" is a length. "7676 square feet" is an area. "4 inches by 7676 square feet" describes a volume, which is equal to 2,558.67 cubic feet. (= 7676/3, because 4 in = 1/3 ft.) So your question is better put as "How many tons of crushed stone does it take to cover an area of 7676 square feet to a depth of 4 inches?" The answer depends on the density of the crushed stone. I can't answer that, but I've given your question a clearer phrasing.
8 cubic feet. (32 sq. ft x 3 inches = 32 x 144 x 3 = 13824 cubic inches There are 1728 cubic inches in a cubic foot. 13824 divided by 1728 = 8).
1 cubic yard equals 27 cubic feet. At a six inch depth 1 cubic foot will cover 2 square feet, so 27 cubic feet will cover 54 square feet.