The dining philosophers problem is a classic synchronization problem in computer science where a group of philosophers sit at a dining table with a fork between each pair of adjacent philosophers. They alternate between thinking and eating, but to eat, a philosopher must have both forks. If multiple philosophers try to pick up their left fork simultaneously, they can create a deadlock. The challenge is to design a solution that ensures all philosophers get to eat without causing deadlock.

philosophers problem is based on dijksta algo, five philosophers spends their whole life in thinking and eating. when one eats she doesn't interact with her collague. there is one table having five plates,five chopstick between each plates and one bowl of rice in the middle.if at the same time, five philosophers gets hungry.they will have only one chopstick in their hand,but for eating two chopsticks will be required. so,this is philosophers problem. for this there are different types of algorithms. one solution will be ,by using semaphores(semaphore is a synchronization tool). semaphores have two values one is semsignal and semwait. solution could be lie this. 1.only odd position philosophers will get hungry at same time and after puting back both chopsticks another can eat. 2.first pickup leftside chopstick then right if it is available.

The semaphore solution for the Dining Philosophers problem is a bowl in the center of the table with two rocks in it. There is also a pile of four forks. (The fifth fork is useless.) When a philosopher wants to eat, he reaches in the bowl for a rock. If he finds one, then he can take two forks and proceed to eat spaghetti. When he is done eating, he first replaces the forks in the pile and then he replaces the rock in the bowl, after which he starts his thinking phase. If there is no rock in the bowl when he goes to get one, he must wait and try again. This is the blocked state.

The names of the philosophers are Thales, Anaximander, and Anaximenes.

the dining room