1. Weigh 80 g NaOH.
2. Put this NaOH in a 1 L volumetric flask.
3. Add slowly 200 mL distilled water and stir.
4. Put the flask in a thermostat at 20 0C and maintain for 1 hour.
5. Add distilled water up to the mark. Stir vigorously.
6. Standardize the solution by titration with oxalic acid, potassium hydrogen phtalate, etc.
7. Transfer the solution in a bottle and apply a label (date, name of the operator, name of the solution, normality).
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.
To prepare a 1N NaOH solution from a 10N NaOH solution, you can dilute it by adding 1 part of the 10N NaOH solution to 9 parts of water. Measure the volume of the 10N NaOH solution needed based on the amount of 1N NaOH solution you want to prepare. Always add the concentrated solution to water slowly and mix well.
To prepare 0.1N NaOH solution from a 1N NaOH solution, you can dilute 1 part of the 1N solution with 9 parts of water (since 1/10 = 0.1). Measure 1 volume of the 1N NaOH solution and add 9 volumes of water to it, then mix well to get your 0.1N NaOH solution.
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.
To prepare a 1N NaOH solution from a 10N NaOH solution, you can dilute it by adding 1 part of the 10N NaOH solution to 9 parts of water. Measure the volume of the 10N NaOH solution needed based on the amount of 1N NaOH solution you want to prepare. Always add the concentrated solution to water slowly and mix well.
To prepare 0.1N NaOH solution from a 1N NaOH solution, you can dilute 1 part of the 1N solution with 9 parts of water (since 1/10 = 0.1). Measure 1 volume of the 1N NaOH solution and add 9 volumes of water to it, then mix well to get your 0.1N NaOH solution.
To prepare a 10 N solution of NaOH, you would dissolve 400 g of NaOH pellets in enough distilled water to make 1 liter of solution. Remember to add the NaOH to the water slowly and carefully due to the exothermic nature of the reaction. Finally, stir the solution until all of the NaOH has fully dissolved.
To prepare a 2.5 N NaOH solution in methanol, you would first calculate the amount of NaOH needed based on its molar mass and the desired concentration. Then, dissolve this amount of NaOH in the appropriate volume of methanol to make the 2.5 N solution. Be sure to wear appropriate safety gear and follow proper handling procedures when working with NaOH.
Since "normality" is defined as the gram equivalent weight of a substance in a liter of solution, a 0.02 N NaOH solution would have 0.02 gram equivalents of NaOH per liter. To reduce it to 0.01 N you need only dilute it to one half of the original - e.g. 500 ml of NaOH mixed with 500 ml of pure water. Because there is a small change in the density upon mixing, the exact amount of water will differ slightly from 500 ml, but for a solution as dilute as 0.02 N, it won't be that far off. The best way to get it exact would be to start with a known volume of 0.02 N NaOH and then add enough water to bring the total to exactly twice the original volume. This might be accomplished by doing it in a graduated cylinder or adding it from a burette into a volumetric flask. the important thing is to know the starting volume of the 0.02 N solution and the final volume of the diluted (0.01 N) solution
The molar mass of NaOH is 40.00 g/mol. Therefore, 40 g of NaOH is equal to 1 mol. Since normality is defined as the number of equivalents of solute per liter of solution, the normality of the 2 L solution containing 40 g of NaOH would be 1 N.
3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.
Take 60 gm NaOH (100%) disolve it in distilled water, and make up to 2.0 liter by distlilled water.the prepared solution is 0.75 N NaoH Solution.
To determine the volume of NaOH solution needed to neutralize an acid solution, you would need to know the concentration of the acid solution and the volume of the acid solution. Using the equation n1V1 n2V2, where n represents the number of moles and V represents the volume, you can calculate the volume of NaOH solution needed.