3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.
The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
Since HCl is a monoprotic acid, its normality is the same as its molarity. A 4 N solution of HCl is a 4 M solution of HCl as well. If you want to make a liter of a 4 N solution of HCl, you need to dilute a certain volume of a standard solution you already have to one liter (1,000 mL) of the 4 M solution. You could use a standard concentrated solution of HCl that is usually 12 M using the following equation: (V1)(M1) = (V2)(M2) V1 = ? M1 = 12 M V2 = 1,000 mL M2 = 4 M V1 = [(V2)(M2)] / ((M1) V1 = [(1,000 mL)(4 M)] / (12 M) V1 = 83 mL According to the above calculations, to make 1,000 mL (1 L) of a 4 M solution of HCl, you would need to dilute with water 83 mL of 12 M solution of HCl to 1,000 mL (1 L) volume. As stated before, a 4 M solution is also a 4 N solution of HCl.
NaOH is a base.
NaOH is a base.
NaOH is a base.
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
No. 3n is not a factor of 3n + 7.
No. 3n is not a factor of 3n + 7.
The GCF is 3n.
25-3n = 22
No. 3n isn't a factor of 3n + 7. The GCF of 3n + 7 and 9n is 1.
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
3n+2+3n+2=6n+4
3n^4 divided by 3n^3 = n
9