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Since HCl is a monoprotic acid, its normality is the same as its molarity. A 4 N solution of HCl is a 4 M solution of HCl as well. If you want to make a liter of a 4 N solution of HCl, you need to dilute a certain volume of a standard solution you already have to one liter (1,000 mL) of the 4 M solution. You could use a standard concentrated solution of HCl that is usually 12 M using the following equation:
(V1)(M1) = (V2)(M2)
V1 = ?
M1 = 12 M
V2 = 1,000 mL
M2 = 4 M
V1 = [(V2)(M2)] / ((M1)
V1 = [(1,000 mL)(4 M)] / (12 M)
V1 = 83 mL
According to the above calculations, to make 1,000 mL (1 L) of a 4 M solution of HCl, you would need to dilute with water 83 mL of 12 M solution of HCl to 1,000 mL (1 L) volume. As stated before, a 4 M solution is also a 4 N solution of HCl.
What else can I help you with?
What is 3N NaOH?
3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many grams of naoh are needed to prepare 500ml of 125M naoh?
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?
To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.
What is 3N NaOH?
3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.
What is the resulting molarity when 100.00mL of a 0.125 M NaOH solutions is diluted to 500mL?
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many grams of naoh are needed to prepare 500ml of 125M naoh?
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
what is (3n)(3n-1)?
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?
To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.
How do you get this 3n plus 2 plus (3n plus 3 - 3n plus 1)?
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
What is the Greatest Common Factor of 3n2 and 3n?
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
How do you prepare 0.6 N NaOH solution?
for NaOH normality = molarity ; hence for 1M(1N) solution you have to dissolve 40 g NaOH in 1L water ...... therfore for 0.1 N soln you have to dissolve 4 g in 1 L water and then standerized it with acid which has known normality
Can we make 1N NaOH solution from 0.1N NaOH solution?
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
Is 3n the gcf of 3n 7 and 9n?
No. 3n is not a factor of 3n + 7.
