1000 kg moving 1 m s or 70 kg at 8 m s?

Answer 1

If the question is analyzed by a non-relastivistic approach of the kinetic energy due to the relatively low velocity of the objects, the equation is:

K = 0.5mv²

where:

K: kinetic energy (Joules)

m: mass of the object (kg)

v: velocity of the object (m/s)

The kinetic energy of object 1 at 1000 kg and 1 m/s is:

K1 = 0.5(1000kg)(1m/s)² = 500 kg-m/2 = 500 J

The kinetic energy of object 2 at 70 kg and 8 m/s is:

K2 = 0.5(70kg)(8m/s)² = 2240 J

If higher energy is preferable, than select object 2.

If lower energy is preferable, than select object1.