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10 grams of NaCl react with excess AgNO3. How many grams of solid AgCl are produced in this reaction?
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4.02 grams of AgNO3 react with excess NaCl how many grams of silver nitrate are produced?
The balanced equation for the reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From the equation, 1 mole of AgNO3 produces 1 mole of AgCl. The molar mass of AgNO3 is 169.87 g/mol, so 4.02 grams is equivalent to 0.024 moles of AgNO3. Therefore, 0.024 moles of AgCl will be produced, which is equivalent to 2.65 grams.
How many grams of silver chloride can be produced from the reaction of 20 g of silver nitrate with an excess amount of sodium chloride AgNO3 (aq) NaCl (aq) AgCl (s) NaNO3 (aq)?
20 grams of silver nitrate would produce an equivalent amount of silver chloride if all the silver nitrate is converted. The molar ratio of AgNO3 to AgCl is 1:1, so 20 grams of AgNO3 would produce 20 grams of AgCl.
How many moles of AgNO3 does 85 grams of AgNO3 represents?
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
How many grams of NaCL are produced when 80.0 grams of O2 are produced?
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
Calculate the mass of AgBr is formed when 35.5mL of 0.184 M AgNO3 is treated with an excess of aqueous hydrobromic acid HBr?
To find the mass of AgBr formed, first calculate the moles of AgNO3 in 35.5 mL of 0.184 M solution. Then, use the mole ratio from the balanced chemical equation between AgNO3 and AgBr to find the moles of AgBr formed. Finally, multiply the moles of AgBr by its molar mass to get the mass. Note that since HBr is in excess, AgNO3 will be the limiting reagent.
4.02 grams of AgNO3 react with excess NaCl how many grams of silver nitrate are produced?
The balanced equation for the reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From the equation, 1 mole of AgNO3 produces 1 mole of AgCl. The molar mass of AgNO3 is 169.87 g/mol, so 4.02 grams is equivalent to 0.024 moles of AgNO3. Therefore, 0.024 moles of AgCl will be produced, which is equivalent to 2.65 grams.
How many grams of silver chloride can be produced from the reaction of 20 g of silver nitrate with an excess amount of sodium chloride AgNO3 (aq) NaCl (aq) AgCl (s) NaNO3 (aq)?
20 grams of silver nitrate would produce an equivalent amount of silver chloride if all the silver nitrate is converted. The molar ratio of AgNO3 to AgCl is 1:1, so 20 grams of AgNO3 would produce 20 grams of AgCl.
How many moles of AgNO3 does 85 grams of AgNO3 represents?
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
How many grams of NaCL are produced when 80.0 grams of O2 are produced?
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
From this reaction 127.1 grams of copper will produce how many grams of silver?
To calculate the amount of silver produced, first find the molar ratio between copper and silver in the balanced chemical equation. For example, if the reaction is 2Cu + AgNO3 -> Cu(NO3)2 + 2Ag, the ratio is 2 moles of silver for every 2 moles of copper. Then, calculate the molar mass of silver (Ag) and use the molar ratio to determine the amount of silver produced from 127.1 grams of copper.
Calculate the mass of AgBr is formed when 35.5mL of 0.184 M AgNO3 is treated with an excess of aqueous hydrobromic acid HBr?
To find the mass of AgBr formed, first calculate the moles of AgNO3 in 35.5 mL of 0.184 M solution. Then, use the mole ratio from the balanced chemical equation between AgNO3 and AgBr to find the moles of AgBr formed. Finally, multiply the moles of AgBr by its molar mass to get the mass. Note that since HBr is in excess, AgNO3 will be the limiting reagent.
How much AgCl is produced when 4.22 grams of AgNO3 react with 7.73 grams of AlCl3?
To find the amount of AgCl produced, first determine the limiting reactant by converting the given masses of AgNO3 and AlCl3 to moles. Then, use the stoichiometry of the balanced chemical equation to calculate the amount of AgCl produced from the limiting reactant. This will allow you to determine the maximum theoretical yield of AgCl.
How many grams of carbon dioxide are produced when 23.5 g of propanol react with excess oxygen in a combustion reaction?
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
How many grams of strontium chloride are produced by the reaction?
The amount of strontium chloride produced in a reaction would depend on the specific reaction involved and the stoichiometry of the reaction. To calculate the grams produced, you would need to know the balanced chemical equation, the amount of the starting materials used, and use stoichiometry to determine the amount of strontium chloride produced.
A solution containing 14 grams of AgNo3 is added to a solution containing 4.83 g of CaCl2. Find the mass of the precipitate produced.?
To find the mass of the precipitate produced, we need to determine which product will precipitate when AgNO3 and CaCl2 react. The reaction will form AgCl, which is insoluble. Therefore, all Ca(NO3)2 will remain in solution, while AgCl will precipitate. Use stoichiometry to determine the mass of AgCl produced from the reaction.
How many grams of carbon dioxide are produced when 23.5 g of 1-heptanol react with excess oxygen in a combustion reaction?
To find the grams of carbon dioxide produced, first determine the moles of 1-heptanol using its molar mass. Then, use the balanced combustion equation of 1-heptanol to find the moles of CO2 produced. Finally, convert moles of CO2 to grams using its molar mass.
What mass of solid agcl is obtained when 25 ml of 0.068m agno3 reacts with excess of aqueous hcl?
To find the mass of AgCl formed, first calculate the number of moles of AgNO3 using the formula moles = Molarity x Volume (in liters). Then, use the balanced chemical equation to determine the mole ratio between AgNO3 and AgCl. Finally, convert the moles of AgCl to grams using the molar mass of AgCl (107.87 g/mol).
