Let the number of boys in class X = a,
The number of girls will be a+3,
Let the number of boys in class X = a, The number of girls will be a+3,
The total number of students is a+a+3=11
2a+3=11
2a=11-3
2a=8
a=8/2
a=4
Therefore, the number of boys is 4, the number of girls will be 4+3 which will be 7. Please let me know if you understand. Thanks.
This is math problem I guess and I am only in 4 th grade
A student may fail mathematics because he/she did not study, did not attend class, or did not understand the lesson material.
A student may fail mathematics because he/she did not study, did not attend class, or did not understand the lesson material.
5
48
fourteen students offers physics only.
25% if 13 is a fractional number. You cannot have a fractional number of students.
about 25
This information tells us that (248/x) = (62/100) , by the definition of percentage. Thus x = 248*(100/62) = 400 so there are 400 students in the class.
8/15
Using set theory let A contain the students who failed mathematics (50) and B contain the students that failed English (30). Now set A and B intersect so they share the same students (5). Therefore the students who passed both subjects is the complement of the union of the sets. ~(AUB)=~(A+B-AintersectB)=100-(50+30-5)=25 students.
Philosophy Advanced Mathematics Teaching Theories Abnormal Psych
ANSWERI believe most classes have a maximum number of thirty students per class, but some have more.