Mass = Moles x Ar = 12.5 x 24 = 300g
A sample of 56,4 of magnesium is equal to 2,32 moles.
1,11 moles of magnesium have 26,97855 g.
This is the amount of magnesium.
There are 0.13 moles in 20 grams of magnesium nitrate.
The formula for magnesium oxide is MgO, showing that each formula unit of magnesium oxide contains one mole of magnesium ions. Therefore, if there is ample oxygen available, 4 moles of magnesium will form 4 moles of magnesium oxide.
88,1 moles of magnesium is equivalent to 2 141,27 g.
4,515.10e24 atoms of magnesium is equal to 7,5 moles.
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
125 g nickel is equivalent to 2,13 moles.
2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.
0.1126g Mg/(24.305g Mg) = 0.004632792 moles Mg You're welcome, noob.
5.05 g/mol