1 cubic feet of concrete requires how much coarse aggregate and fine aggregate?

Answer 1

it should depend in which construction you going to be used the concrete....means it is used in a house or in a big project like a massive dam...........

like the ratio of "C:S:A "

C= CEMENT S= SAND(FINE AGREEGATE) A=AGREEGATE (COARSE AGG)

IN SOME TIME IT USED AS THE RATIO OF 1:2:4

OR 1:1.5:3 AND RATIO IS USED TO FIND THE QUANTITY OF SAD AND AGREEGATE...............

1 cubic feet of concrete requires how much coarse aggregate and fine aggregate?ANSWER :

Grade is M20 and ratio for M 20 is 1:1.5:3

void ratio for cement is 100 % compressive

void ratio for fine aggregate 20 %

void ratio for coarse aggregate 32% , from IS code

NOTE : (that means cement have compressive in 100%

fine Aggregate needs compressive in 20 %

coarse Aggregate needs compressive 10 32 % , from IS code )

total ratio for mix is 1.52

cement = 1

fine aggregate = 1.5

coarse aggregate = 3

total is 1 + 1.5 + 3 = 5.5

take now all dimension meter only , convert it in feet with end of the solution

CEMENT = [(1 X 1 X 1.52 X) / 5.5 ]= 0.28 m³

1 is required quantity

Another 1 is cement ratio

1.52 is total compressive for concrete

Total ratio is 5.5

50 Kg per bag of cement is 0.0347 m³

No of bags required for 1 m³ of concrete is

.28 m³ / .0347 m³ = 8.07 bags take 8 bags

CEMENT = 9.88 cubic feet

FINE AGGREGATE = [ ( 1 X 1.5 X 1.52 ) / 5.5 ) = 0.41 m³

Here 1.5 is fine aggregate ratio , remaining is same as above.

1 m³ = 35.29 cubic feet

1 cubic feet = .03 m³

F.AGG = 14.47 cubic feet

COARSE AGGREGATE = [ ( 1 X 3 X 1.52 ) / 5.5 ) = 0.83 m³

Here 3 is ratio of coarse aggregate

C. AGGREGATE = 29.29 cubic feet

ANS :

CEMENT = 9.88 cubic feet

F.AGG = 14.47 cubic feet

C. AGGREGATE = 29.29 cubic feet

Note : [ 100 cubic feet is 1 brass

1 m³ = 35.29 f³

1 f3 = 1 m³ / 35.29 = 0.03 m³