1000 mmol = 1 mol. So, what you do is 2.55mmol*(1mol/1000mmol). The mmol's cancel and you are left with mol.
The "m" is a metric prefix. So, 1000mN = 1N just like 1000mmol = 1mol.
The mass of a 10 mmol solution will depend on the molar mass of the solute. To calculate the mass, multiply the number of moles (10 mmol) by the molar mass of the solute in grams/mole.
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
Molarity, abbrev. M, units: mol/L, mmol/ml
The answer is 0,02552 mmol.
Mmol stands for millimole, which is a unit of measurement used in chemistry and medicine to represent amount of a substance based on the number of moles present in a sample. It is equal to one-thousandth of a mole.
divide mmole by 1000 to get mole .
The mass of a 10 mmol solution will depend on the molar mass of the solute. To calculate the mass, multiply the number of moles (10 mmol) by the molar mass of the solute in grams/mole.
1 mol = 103 mmol Conversely, 1 mmol = 10-3 mol For example: 25 mol x 103 mmol/1 mol = 25000 mmol and, 3.2 mmol x 10-3 mol/1 mmol = 0.0032 mol
1) Convert to moles. I assume mmol means minimole, so you divide by 1000. 2) Multiply the number of moles by the atomic or molecular weight. The molecular weight is different for different substances; you'll have to look it up or calculate it.
To find the moles of solute, first calculate the amount of CaCl2 in the solution: 17.33 mL * 2.17 mol/L = 37.6561 mmol of CaCl2. Then convert this to moles: 37.6561 mmol / 1000 = 0.0377 mol of CaCl2 in the solution.
Milli equivalents and milli moles are units used to describe molecular or ionic grades of concentration. A milli equivalent or mEq is derived by dividing the concentration in millimol or mmol by the valency of the ion involved.Eg: 1 mEq of sodium Na+ = 1 mmol of sodium (because valency is 1)whereas 1 mEq of Ca2+ = .5 mmol of calcium. (because valency is
All one to one here. NaOH + HCl --> NaCl + H2O So, getting the moles of either product tell you how many moles H2O produced. Molarity = moles of solute/Liters of solution moles of solute = Liters of solution * Molarity ( 30.00 mL = 0.03 liters ) Moles H2O = 0.03 Liters * 1 M 0.030 moles H2O produced =================
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.