Balanced equation.
KOH + HBr -> KBr + H2O
everything is one to one, so...
Molarity = moles of solute/liters of solution ( change ml to liters )
0.25 M KOH = moles KOH/0.015 liters
= 0.00375 moles of KOH
this is as many moles that you have of HBr, so...
Molarity of HBr = 0.00375 moles/0.012 liters
= a concentration of HBr that is 0.31 M
16 / 120 * 100% = 13.3% (w/w)
it is primary standard........ but before making solution dry it at 120. C
Just add the two masses: 40 + 120 = 160 grams.
90 litres
It's 1.5 M
16 / 120 * 100% = 13.3% (w/w)
0.6
6 molar
The GCF is 24.
120 m^3 = 120,000,000 cm^3.
The greatest common factor of 48, 69 and 120 is 3
If that's 8x = 120, x = 15
it is primary standard........ but before making solution dry it at 120. C
0,288 moles
480ml
The answer is too long to type on here but you can get a solution on your TI-89 go to Math 7:Probability 1:! then type in 120! 120!=66895029134491270575881180540903725867527463331380298102956713523016335.. =(roughly) 6.6895x10198
30% is same as 0.3. Multiply that value by $120 to obtain $36 off. Revised Solution: 30% off of $120 = $64 = 30% discount applied to $120 = $100 - (30% * $120) = $100 - (0.30 * $120) = $100 - $36 = $64