Just add the two masses: 40 + 120 = 160 grams.
This is a homogeneous solution of ammonium hydroxide in water.
The molarity is 0,031.
The mass is 234,8 g.
1,574 mol/L NaCl
1.47g
0.27 M
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
The answer is 15,039 g hydrogen chloride (HCl).
mixture
4 milliequivalents of sodium chloride solution is a solution having 0,2338 g in 1 L.
You get salt at the bottom of the pan!
50 g of potassium chloride are dissolved in 100 g water at cca. 80 oC.
This is a homogeneous solution of ammonium hydroxide in water.
Molarity = moles of solute/liters of solution 2500 milliliters = 2.5 liters ------------------------------------ 12.2 grams SrCl2 (1 mole SrCl2/158.52 grams) = 0.07696 moles strontium chloride -------------------------------------------------------------------------------------------------------- so, Molarity = 0.07696 moles SrCl2/2.5 liters = 3.07 X 10 -2 M SrCl2 -------------------------------------
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
The molarity is 0,031.