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Voice comes in 8000 Hz frequency, so 16000 samples required each seconds.

1 sample if of 8 bits.

16000 sample if of 128000bits.

these bits is send per second.

so bandwidth required is 128kbs for single voice.

for 24 it is 24 x 128 kbps

= 3072 kbps

= 3.1 mbps

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12y ago
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11y ago

4,000 Hz is the standard transmission frequency for voice.

4,000 Hz * 2 = 8,000 samples per second (sps)
8,000 sps * 8 bits per second (bps) = 64,000 bps
24 * 64,000 bps = 1,536,000 bps

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Q: 24 voice signals are to be transmitted over a single phone line. What is the bandwidth required if the standard analog-to-digital sampling rate is used and each sample is converted into an 8bit value?
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