R1+ R2 = 2 (1)
1/R1 + 1/R2 =1/2 => R1 x R2 /(R1 +R2) = 2 (2)
(1) and (2) => R1 x R2 / 2 = 2 => R1 x R2 = 4 => R1 = 4 / R2 (3) (1) and (3) => 4/R2 + R2 =2 => 4 + R2 2 = 2 R2 => R22 - 2R2 + 4 =0 (4)
delta = (-2)2- 4 *4 = -12 delta is negative which means that the equation's solution has an imaginary part,hence no real solution for the equation
The resistance of two resistors R1 and R2 in parallel is R1R2/(R1+R2), so the resistance of 1 ohm in parallel with 2 ohms is 0.67 ohms.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
If the voltage and resistance values remain the same the power dissipated will be 90 W.
Resistors can, in fact, be connected in four different ways. These configurations are termed:seriesparallelseries-parallelcomplex
A fuse will not work successfully if it is connected in parallel with the device it is supposed to protect.First, it will blow because it has no resistance in series with it. Second, once it blows, the device still has power applied to it. Fuses must be wired in series.
A voltmeter is used to measure potential difference across two points in an electrical circuit . The voltmeter is connected in parallel across the circuit element (resistance ) so that its inclusion in the circuit has negligible effect on total resistance and current flowing in yhe circuit A voltmeter has high resistance,if connected in series it will increase of circuit and reduce the current in the circuit
Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
When many resistances are connected in series, the equivalent resistance is greater than the greatest single resistance. When many resistances are connected in parallel, the equivalent resistance is less than the smallest single resistance.
Let the equivalent resistance be R and let there be 3 resistors namely R1,R2 and R3, connected in a parallel way. Now, the relation is: 1/R = 1/R1 + 1/R2 + 1/R3
The resistors should be connected in parallel .
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
it depends on how we are connecting them.if 5 1 ohm resistors are connected in series then the equivalent resistance is 5 ohms.if they are connected in parallel then the equi resistance is 1/5 ohms.
To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)
The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
Resistors in series add resistance to an electrical circuit. For instance two 1 ohm resistors in series will have 2 ohms of resistance. Resistors in parallel divide the resistance between them. Thus two 2 ohm resistors in parallel will have 1 ohms total resistance. resistors of different sizes work the same way. a 4 ohm and 2 ohm resistor in series have 6 ohms resistance. While in parallel they will have .75 ohm resistance. resistance formulas: series: Req = r1+r2+r3....+rx parallel: Req = 1/r1 + 1/r2 + 1/r3 ..... +1/rx