Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example:
The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms.
The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
I am assuming you are referring to an IC in the electronics sense (Integrated circuit). If so, an IC works by utilizing a large array of resistors printed onto many layers of silicon. By using these resistors an IC can perform many functions that would normally require a large amount of components. A simple IC may have only 2 or 3 resistors on it, whereas a complex one can contain up to 10,000 (and yes more are possible)
1)Transistors 2)Capacitors 3)Resistors
1.costly 2.replication 3.complex
Like-minded
It's a rectangle.
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
2 ohms. It is like connecting two 3 ohm resistors in series and then these two series resistors are connected in parallel with third 3 ohm resistor in parallel
2 amps
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
R1+ R2 = 2 (1)1/R1 + 1/R2 =1/2 => R1 x R2 /(R1 +R2) = 2 (2)(1) and (2) => R1 x R2 / 2 = 2 => R1 x R2 = 4 => R1 = 4 / R2 (3) (1) and (3) => 4/R2 + R2 =2 => 4 + R2 2 = 2 R2 => R22 - 2R2 + 4 =0 (4)delta = (-2)2- 4 *4 = -12 delta is negative which means that the equation's solution has an imaginary part,hence no real solution for the equation
2 in series with 3&4 in parallel
Resistors in series add resistance to an electrical circuit. For instance two 1 ohm resistors in series will have 2 ohms of resistance. Resistors in parallel divide the resistance between them. Thus two 2 ohm resistors in parallel will have 1 ohms total resistance. resistors of different sizes work the same way. a 4 ohm and 2 ohm resistor in series have 6 ohms resistance. While in parallel they will have .75 ohm resistance. resistance formulas: series: Req = r1+r2+r3....+rx parallel: Req = 1/r1 + 1/r2 + 1/r3 ..... +1/rx
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
Four 4 ohm resistors in parallel have an equivalent resistance of 1 ohm. Two resistors R1 and R2 in parallel have an equivalant resistance of R1R2/(R1+R2). Plug in 4 ohms for two of the resistors and you get 2 ohms. Repeat and you get 1 ohm.
I have two resistors, a 2-ohm and a 3-ohm.What is their combined effective resistance when they are connected in series ?Answer: R1 + R2 = 5 ohmsWhat is it when they are connected in parallel ?Answer: 1 / [ (1/R1) + (1/R2) ] = 1.2 ohms
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.