Yes. When resistors are connected in "parallel" (all the left ends connected together and all the right ends connected together) the effective resistance is always less then the smallest resistor in the group. For example If you connected a 2 ohm in parallel with a 4 ohm the effective resistance is 1.33 ohm. To your question; if you connect N equal resistors R in parallel the effective resistance would be R/N . The formula for calculating effective resistance R of a group R1, R2, R3, ... in parallel is: 1/R = 1/R1 + 1/R2 + 1/R3 + .... Note; write the right side as a single fraction by getting a common denomenator then invert to get R.
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
Typically, a 100 ohm resistor is used to connect a 1.5 volt led to a series 220v ac adapter. Many LEDs can be connected into a string using the resistors.
Only if you connect then in series. RSERIES = Summation1toN (RN) RPARALLEL = 1 / Summation1toN (1 / RN)
first you need a analog multimeter. put in your meter in the ohm section x10. then remove the cap in the ckt and discharge that. then connect the multimeter -ve probe to the cap +ve terminal and connect the other terminals.the needle comes to low value then com to infinity, remove the probs then connect multimeters -ve prob to the cap -ve terminal that time look carefully the meter's needle comes to the one value and go back to the infinity that the low value is capacitors equivalent resistance value. the cap is 1000uf the equivalent resistance value is around 15 at x10 .the cap is 100uf the equivalent resistance value is around 15 at x100
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
When many resistances are connected in series, the equivalent resistance is greater than the greatest single resistance. When many resistances are connected in parallel, the equivalent resistance is less than the smallest single resistance.
connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
The resistors should be connected in parallel .
Connect 50 of them in series. This would have 50 ohm as equivalent. Same way have another 50 pieces in series. This again would have 50 ohm as effective value. Now connect these in parallel to each other. Now the effective would become as 25 ohm.
You can achieve an effective resistance of 3 ohms by connecting the resistors in series. Connect two resistors in series to get a combination of 4 ohms. Then, connect this combination in parallel with the third resistor to achieve an overall resistance of 3 ohms.
I'm going to take this as "How do you connect resistors is series?" just connect one wire of the first resistor to one wire of the second.
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
Resistors in series add resistance to an electrical circuit. For instance two 1 ohm resistors in series will have 2 ohms of resistance. Resistors in parallel divide the resistance between them. Thus two 2 ohm resistors in parallel will have 1 ohms total resistance. resistors of different sizes work the same way. a 4 ohm and 2 ohm resistor in series have 6 ohms resistance. While in parallel they will have .75 ohm resistance. resistance formulas: series: Req = r1+r2+r3....+rx parallel: Req = 1/r1 + 1/r2 + 1/r3 ..... +1/rx
of course.... next question...
If you're sure that every resistor is exactly 10 ohms, and you need exactly13.75 ohms, then you can do it this way:-- Connect four resistors in parallel. Effective resistance of the combination = 2.5 ohms.-- Connect eight resistors in parallel. Effective resistance of the combination = 1.25 ohms.-- Connect in series: the 4-resistor unit, the 8-resistor unit, and a single 10-ohm resistor.Effective resistance of the combination = (2.5 + 1.25 + 10) = 13.75 ohms.In the real world, however, the combination of (2.5 + 10) = 12.5 would be closeenough to work. And actually, a single 10-ohm resistor might be close enough.Or you could just connect a single 10-ohm resistor to the ohm-meter, take afingernail file, file a small notch in the side of the resistor while watching themeter, stop filing when the resistance arrives at 13.4 ohms, see what it is whenit cools from all the filing and settles down, then make small additional scrapesuntil you have your 13.75 ohms. This might be just as fast as the 23 solder-joints required for the procedure described above, and you save 12 resistors !So what could be bad ! ?