connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
1). Voltage = (resistance) x (current)2). Current = (voltage) / (resistance)3). Resistance = (voltage) / (current)I think #2 is Ohm's original statement, but any one of these can be massaged algebraicallyin order to derive the other two.
5CommentThe plural of ohm is ohms, not ohm's!
Total resistance is 120 ohms. The 120VAC will be split evenly over this 120 ohm load, so every ohm of resistance gets a volt. So there will be a 40 volt drop across the 40 ohm resistor.
Equation of Equivalent Resistance in Parallel is 1/Equivalent Resistance = 1/Resistance 1+ 1/Resistance 2 +1/Resistance 3If the resistance of the resistor is 3 Ohms then1/Req= 1/3 + 1/3 = 1/31/Req= 3/3Then cross multiply so3Req = 3Then isolate variable for Req (divide both sides by 3)answer1 Req= 3/3=1 OhmEquivalent Resistance is 1 Ohm
Where: V = Voltage (Volts), A = Current (Amps) and R = Resistance, (Ohms)Here are a few easy and related equations.V = A * RR= V / AA = V / RSo we have R=3 and A =6 and using the V=A*R equation we getVolts = A(6)*R(3) = 18 Volts.
2 in series with 3&4 in parallel
The equivalent resistance of the parallel combination is 2/3 ohm.
10 Ohms.
It depends on the resistance of each resistor. If each resistor, for example, is 0.333 ohm, then you could connect them in series. If each resistor, for example, is 3 ohms, then you could connect them in parallel.
You can achieve an effective resistance of 3 ohms by connecting the resistors in series. Connect two resistors in series to get a combination of 4 ohms. Then, connect this combination in parallel with the third resistor to achieve an overall resistance of 3 ohms.
1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:Total resistance = 3 ohms.Current in the loop = 6/3 = 2 amperesPower dissipated by the 2-ohm resistor - I2R = 8 watts.2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallelThe 12-ohm resistor is irrelevant.4 volts across the 2-ohm resistor.Power dissipated by the 2-ohm resistor = E2/R = 8 watts.
1). Voltage = (resistance) x (current)2). Current = (voltage) / (resistance)3). Resistance = (voltage) / (current)I think #2 is Ohm's original statement, but any one of these can be massaged algebraicallyin order to derive the other two.
3
The equivalent resistance in a parallel circuit is given by the formula: 1/Rt = 1/R1 + 1/R2. Plugging in the given values (R1 = 1 ohm, R2 = 3 ohm), we get 1/Rt = 1/1 + 1/3 = 4/3. Therefore, the total resistance (Rt) is 3/4 ohm or 0.75 ohm.
By ohm's law, R = V/I. Given V = 9 V and I = 3 A. Plugging this we get, R = 9/3 = 3 ohm. Hence the resistance value in the circuit is 3 ohm.
5CommentThe plural of ohm is ohms, not ohm's!
2 ohms. It is like connecting two 3 ohm resistors in series and then these two series resistors are connected in parallel with third 3 ohm resistor in parallel