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1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:

Total resistance = 3 ohms.
Current in the loop = 6/3 = 2 amperes
Power dissipated by the 2-ohm resistor - I2R = 8 watts.


2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallel

The 12-ohm resistor is irrelevant.

4 volts across the 2-ohm resistor.
Power dissipated by the 2-ohm resistor = E2/R = 8 watts.

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Q: Calculate the power used in 2ohm resistor in each what circuits- 1 a 6V battery in series wid 1ohm and 2ohm resistors 2 a 4V battery in parallel wid 12ohm and 2ohm resistors?
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