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Did the the total voltage across the resistors does not depend on the resistor value?
Wiki User
∙ 14y ago
It depends on where and how the resistor is placed in a circuit. A string of series resistors will split the voltage across all them depending on their values. All of the resistors in parallel will have the same voltage across all of them no matter what their resistance is.
Wiki User
∙ 14y ago
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What value resistor will you need?
That will depend on the specific design needs.
A 120 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source what is the current running through the 40ohm resitor?
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
What does the amount of energy released per charge depend on?
voltage
What two factors determine the output energy of a battery?
The energy delivered by a battery would depend on-- the battery's voltage-- the resistance of the load connected across its output terminals-- the length of the time the load is connectedThe power delivered by the battery is [ (voltage)2 divided by (load resistance) ].The total energy delivered by the battery is [ (power) multiplied by (time the load is connected) ].
On what factors does the amount of heat produced in an electric wire depend?
-- The resistance of the wire.AND-- The voltage between the ends of the wire.OR-- The current through the wire.
You are just asking that let us assume you have connected 2 or 3 resistors in a circuit and the current flowing through the circuit and from all the resistors will be same but how?
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
Does Kirchhoff current law and Kirchhoff voltage law depend on the relationship between current and voltage in a resistor?
Kirchhoff's Voltage and Current Laws apply to circuits: series, parallel, series-parallel, and complex.If your circuit comprises just a single resistor, then they still apply. For example, the voltage drop across a single resistor will be equal and opposite the applied voltage (Kirchhoff's Voltage Law), and the current entering the resistor will be equal to the current leaving it (Kirchhoff's Current Law).
What is the measured voltage across the 680 ohms resistor?
No one is going to be able to tell you that. You are looking for the measured voltage, so go and measure it. In any case, if you were just looking for the voltage it will depend on the circuit current. You can work it out using ohms law (Voltage = Current * Resistance).
Two resistors are connected in a parallel to a batterywhat is the voltage across these two resistors?
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
Why is voltage constant in parallel dc circuit?
depend on the R value(s) because V Source = Sum of individual voltage across each R in the series so if R in the series are equal value, then their V are the same and their V total will be equal of the V Source
How can you change high volts to 9 volts?
A voltage divider (two resistors in series) will achieve the required result. The value of the resistors will depend on what current is required to be supplied. It also matters what variation from 3V is allowed since taking current will make the voltage drop. An electronics parts shop will sell components to make a more efficient system. Or you could get 3 voltage regulators .. 9V then 5V then 3V in series .. that should keep the voltage stable as long as the 9V supply is
When a Resister is jumpered out what is the voltage across the resistor?
A Resistor [note spelling] when jumpered-out has a theoretical resistance of zero. The voltage across same is zero. To "jumper-out" is presuming a wire across the resistor: Theoretically this "ideal" wire has zero resistance, however, in practice a "thin" copper wire of (say) 10mm length - e.g., about the length of a 1/8th-watt resistor - would have a resistance around the milliohm. Depending on the current passing through a wire (per V=IR) the voltage might be nothing or a mega-volt, as a function of the current and cross-section of the wire. However, anything over, say, a small number of amps through a real-world "thin" wire would cause the wire to act as a fuse and break, so, in the case of a thin wire (0.25 mm say) we're looking at near zero volts across the resistor/wire combination at say 0.01 Amps and tending the supplied voltage at, say, 10 amps. If, on the other hand, the resistor is no longer in the circuit (literally "jumpered out") then the theoretical resistance of the "gap" where the resistor should be is infinity (real-world: The order of megaohms). The makes the voltage across same just about the voltage supplied to either side of said resistor as if it were not there, which will depend on the rest of the circuit.
The total resistance in a series connection is equal to product of the individual resistance?
Yes. Power(P)=Current(I)xVoltage(E) or P=I x E, and since in a series circuit current is constant and voltage is additive then: P(series)=Pr1+Pr2+Pr3........ Actually, power dissipated in series circuits is P = I^2 * R and in parallel power dissipated = V^2/R
If you know the current through one resistor in a DC circuit then do you know the current through all the other resistors?
No. Current and voltage are directly proportional to one-another and both are related to resistance by Ohm's law: V = IR or Volts = Current * Resistance So the current will depend upon the voltage and the circuit resistance by rearranging the above equations: I = V/R Meaning that the current will decrease as circuit resistance is increased if the voltage remains constant.
If current drop does it effect the voltage?
Generally, yes. It would depend on the device you are talking about. In a resistor a change in current will result in an instant change in voltage. Inductors and capacitors do not change instantaneously but will over time.
Why would houses have parallel circuits?
So that the voltage across all devices is the same. In a series circuit voltage would vary across each load so would depend on what else was in the circuit.
What is the highest and lowest voltage of an electromagnet?
The strength of an electromagnetic is determined completely by the current through its coil, and doesn't depend on the voltage across the coil. The voltage will be (current) x (resistance of the coil).
