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No one is going to be able to tell you that. You are looking for the measured voltage, so go and measure it. In any case, if you were just looking for the voltage it will depend on the circuit current. You can work it out using ohms law (Voltage = Current * Resistance).

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Q: What is the measured voltage across the 680 ohms resistor?
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What is a fixed resistor measured in?

Resistance is measured in ohms.


What is the voltage across a 60.0 ohm resistor with a current of 3 13 amp?

V = IR Voltage (V, measured in volts) = Current (I measured in amps) times Resistance (R, measured in Ohms) Is your current 3.13? I'm not sure what you wrote there, but just multiply your current times your resistance.


What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?

There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.


The voltage drop in each resistance is?

V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.


What size of resistor is required to operate the LED from a 9V battery?

In order to determine what size of resistor is required to operate an LED from a 9V battery, first start by knowing the current and voltage required for the LED. That information is available in the LED's specifications. For discussion purposes, lets assume a typical LED at 2.5V and 50mW. The translates to a forward current of 20mA. Build a simple series circuit containing a 9V battery, a resistor of an as yet unknown value, and the LED. By Kirchoff's current law, the current in the LED is the same as the current in the resistor, which is also the same as the current in the battery. This is 20ma. By Kirchoff's voltage law, the voltage across the LED plus the voltage across the resistor equals the voltage across the battery. This is 6.5V. (9 - 2.5) By Ohm's law, resistance is voltage divided by current, so the resistor is 6.5 / 0.02, or 325 Ohms. The nearest standard value to that is 330 Ohms. Cross check the power through the resistor. Power is voltage times current, or 6.5V times 0.02A, or 0.13W. A half watt resistor is more than adequate for this job.

Related questions

What does resistor perform?

A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.


What is a fixed resistor measured in?

Resistance is measured in ohms.


What is the voltage across a 60.0 ohm resistor with a current of 3 13 amp?

V = IR Voltage (V, measured in volts) = Current (I measured in amps) times Resistance (R, measured in Ohms) Is your current 3.13? I'm not sure what you wrote there, but just multiply your current times your resistance.


If the resistance in ohms is higher than the voltage what does that mean?

Voltage is not measured in ohms. It is measured in volts.


Is resistor measured in amps?

No, a resistor isn't measured at all. A resistor has a quality called "resistance" - and that value is measured. Resistance is measured in Ohms.


What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?

There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.


The voltage drop in each resistance is?

V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.


A 2200 watt resistor operating at 110 volts conducts amps of current?

Don't follow what a '2200watt resistor' is. A resistor spec is measured in ohms. Ohms Law is expressed as: Voltage drop = current x resistance, and the wattage of the resistor is = volts drop x current. You have to decide if your resistor is 2200 ohms, or is taking 2200 watts. These two alternatives will give different results for the current. If it is 2200 watts, at 110 volts, the current is 20 amps. If it is 2200 ohms, at 110 volts, the current will be 50 milliamps. (0.05amps)


What size of resistor is required to operate the LED from a 9V battery?

In order to determine what size of resistor is required to operate an LED from a 9V battery, first start by knowing the current and voltage required for the LED. That information is available in the LED's specifications. For discussion purposes, lets assume a typical LED at 2.5V and 50mW. The translates to a forward current of 20mA. Build a simple series circuit containing a 9V battery, a resistor of an as yet unknown value, and the LED. By Kirchoff's current law, the current in the LED is the same as the current in the resistor, which is also the same as the current in the battery. This is 20ma. By Kirchoff's voltage law, the voltage across the LED plus the voltage across the resistor equals the voltage across the battery. This is 6.5V. (9 - 2.5) By Ohm's law, resistance is voltage divided by current, so the resistor is 6.5 / 0.02, or 325 Ohms. The nearest standard value to that is 330 Ohms. Cross check the power through the resistor. Power is voltage times current, or 6.5V times 0.02A, or 0.13W. A half watt resistor is more than adequate for this job.


What is the unit used of resistor?

The ohm. It is how much resistance a component or part of a circuit has to the flow of electrical charge when a voltage is induced across it.


What voltage is developed across a 6 Ω resistor if 3 A of current flows through it?

The answer is 6 ohms x 3 amps which is 18 v.


What is the voltage difference across a 30- resistor if a 0.5 amp current is flowing through it?

30 ohms x 0.5 amp, that is 15 v.