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What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?
Wiki User
∙ 13y ago
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
Wiki User
∙ 12y ago
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How measure the value of resister?
To measure the value of a resistor, apply a voltage and measure the voltage across the resistor and the current through the resistor. Use Ohm's law: Resistance equals Voltage divided by Current. Start with a small voltage and increase gradually until a reading is obtained, but be careful that the power dissipation (watts = volts times amperes) of the resistor is not exceeded. Simpler solution: Use an ohmeter.
If V in battery voltage equals 5volts Resistor 1 equals 6ohms and Resistor 2 equals 4ohms What will be the volt meter Vout read?
4.5 Volts
How do you calculate electrical power?
Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.
What is the current if voltage equals 14.4 V and resistance equals 1.6 ohms?
I = V / R = (14.4 / 1.6) = 9 AmperesNote: Stand back! The resistor dissipates 129.6 watts.
If you know the voltage applied to a resistor and the value of the resistor how would you determine the power dissipated in the resistor.?
Power dissipation of a resistor or any load is the amount of power (in watts) that is converted to heat, light, or other form of energy. In a resistor, power dissipation is defined by Ohm's law P = I^2 * R Power dissipated equals current through the resistor squared times the resistance in ohms. Since the power is converted to heat, a resistor has a maximum dissipation rating set by the manufacturer, above which the resistor will be damaged.
What is the voltage drop of a 1k ohm resistor?
It depends on the current going through it. Ohm's law: Voltage equals current times resistance.
What is the current through a 1.5k resistor with voltage of 3V across it?
Two milliamperes. Ohm's law: Current equals voltage divided by resistance.
How measure the value of resister?
To measure the value of a resistor, apply a voltage and measure the voltage across the resistor and the current through the resistor. Use Ohm's law: Resistance equals Voltage divided by Current. Start with a small voltage and increase gradually until a reading is obtained, but be careful that the power dissipation (watts = volts times amperes) of the resistor is not exceeded. Simpler solution: Use an ohmeter.
If V in battery voltage equals 5volts Resistor 1 equals 6ohms and Resistor 2 equals 4ohms What will be the volt meter Vout read?
4.5 Volts
When the current traveling through a resistor is increased what happens to the voltage that travels through the same resistor?
Your question reveals fundamental misunderstandings about the nature of electricity.'Voltage' is simply another word for 'potential difference', and a potential difference appears across opposite ends of the resistor; it doesn't 'travel through' that resistor! Current, on the other hand, DOES 'travel through' the resistor and is caused by the potential difference across the resistor.Resistance is the ratio of potential difference to current. So if the resistance remians unchanged when the current through it doubles, then it has happened because the potential difference has doubled.
What is the voltage drop through a resistor of 6 ohms and 2 amps?
12 volts...! The voltage drop across a 2 ohm resistor depends on the current flowing through it. As voltage (E) equals current (I) times resistance (R), if 1/2 amp is flowing through your 2 ohm resistor, 1/2 times 2 = 1 volt. If 1 amp is flowing through your 2 ohm resistor, 1 times 2 = 2 amps. Piece of cake. If the two ohm resistor is the only component in the circuit, it will drop whatever the applied voltage is. Put a 2 ohm resistor across a 6 volt battery, it drops 6 volts. If you put your 2 ohm resistor across a 9 volt battery, it drops 9 volts. Another way to say voltage drop may help. The voltage drop across a resistor is the voltage it "feels" when in a circuit. And that last couple of examples says that very well. In a circuit where a given resistor is the only component, it drops all the voltage in the circuit. It "feels" all the voltage in the circuit. In a circuit where there are 2 resistors of equal value in series, each one drops or "feels" half of the applied voltage. (The sum of the voltage drops equals the applied voltage.) As you work more with simple circuits using resistors in different arrangements with a given voltage source, try thinking of the voltage drop of a resistor as the voltage it "feels" when the circuit is energized.
How do you calculate electrical power?
Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.
What is the power dissipated by a resistor that has 5 amps flowing through it with 120 volts applied?
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
If the volts going in equals 5 and there is a resistance that equals 6 what would be the volts coming out?
The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
How can you convert a resistor of 270.4 watts to ohms without having been given voltage or current?
There is no way to make the conversion. The wattage given as that of the resistor is only the amount of power it is dissipating. It's the heat the resistor is radiating. The resistor is said to be using or radiating 270.4 watts. (That's a lot of wattage! How hot would a 270 watt incandescent lamp get? Very hot.) A watt is sometimes called a volt-amp. That's because watts equals volts times amps. And it's easy to see how that works with an example including the approximately 270 watts set down in the question. As regards that approximately 270 watts specified, if the resistor was a 1 ohm resistor and had 270 amps of current flowing through it, the 270 watts would be the wattage the resistor would be radiating. If the resistor was a 270 ohm resistor and had 1 amp of current flowing through it, it would (also) be radiating 270 watts. See how that works? An unlimited number of variations on the theme exist. To find the resistance of the resistor, one of two things must be known in addition to the wattage the resistor is running at. Either the voltage across the resistor or the current flow through the resistor must be specified to "finish" the problem.
Why the capacitor time period formula is given as t equals RC?
-- The quantity 'RC' has the physical dimensions of Time. -- If the capacitor is charging through a resistor, then 'RC' is the time it takes to charge up to (1 - 1/e) of the voltage it still has to go to become fully-charged. -- If the capacitor is discharging through a resistor, then 'RC' is the time it takes to discharge to 1/e of its present voltage. -- ' e ' is the base of natural logarithms, approximately 2.71828... -- 'RC' is called the 'time constant' of the resistor/capacitor combination.
What is the current if voltage equals 14.4 V and resistance equals 1.6 ohms?
I = V / R = (14.4 / 1.6) = 9 AmperesNote: Stand back! The resistor dissipates 129.6 watts.
