Your question reveals fundamental misunderstandings about the nature of electricity.
'Voltage' is simply another word for 'potential difference', and a potential difference appears across opposite ends of the resistor; it doesn't 'travel through' that resistor! Current, on the other hand, DOES 'travel through' the resistor and is caused by the potential difference across the resistor.
Resistance is the ratio of potential difference to current. So if the resistance remians unchanged when the current through it doubles, then it has happened because the potential difference has doubled.
Your question needs rephrasing; as it stands, it makes no sense.
Adding more components changes how a resistor works. In a series circuit, resistance goes up, slowing current. In a parallel circuit, resistance drops, letting more current flow. The effect depends on how the components are connected.
when the frequency is increased the total impedance of a series RC circuit is decrease.
what happens if we remove Rc in RC coupled amplifier
Are you talking about delaying the release of a relay? or actually slowing down the mechanism so it doesn't "Click". You'll NEVER get rid of the click, the inside of that consists of a metal arm attached to a spring. When current is applied, an electromagnet pulls the arm toward it and completes the circuit, it snaps because this happens very quickly. When the current is removed the spring snaps it back into its original place. If you want to slow down the release, put a capacitor and resistor in front of it. The capacitor stores the charge, while the resistor limits how fast it discharges. The actually capacitor values and resistor values will vary with how much current needs to be applied to keep the relay closed, and the length of time you want to keep it that way. (+)-------[Capacitor]-----[Resistor]------<Your Relay>--------(-)
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
it explodes and burns everyone in the room.
When the voltage is increased across a metal film resistor, the current flow will also increase. Ohm's law states that the current flowing through a resistor is directly proportional to the voltage across that resistor. I = V/R Let us assume an initial voltage drop across a 4.99K ohm metal film resistor is 5V. The current flow through the resistor is calculated to be: I = 5/4990 = 0.001 Amps or 1 mA If that voltage were to say double to 10V: I = 10/4990 = 0.002 Amps or 2 mA Using these values it is also possible to calculate the power dissipated by the resistor. P = I*V = 0.002 * 10 = 0.02 Watts This power calculation determines the minimum physical case size needed for the resistor to function within these conditions. Anything smaller, the resistor will fail.
the current flowing in will be low
Voltage, current, and resistance can be related by this formula. V = iR, where I is the current. Assuming that the voltage stays constant, current will decrease. Hope this helps!
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
current through the switch become 0.and switch become a high value resistor.
current through the switch become 0.and switch become a high value resistor.
That sounds like a resistor. However, please note that "slow down a current" is not a very accurate description of what happens. What the resistor does is take energy away from the current.
Eliminating the ballast resistor will cause excess current through the coil, and will cause excess current through the points.When that happens, the points and/or coil will fail prematurely.
The flow of electrons meets an increased impedance to it's flow.
The flow of electrons meets an increased impedance to it's flow.