The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
The current I = 0.18257 amperes. Scroll down to related links and look at "Electrical voltage V, amperage I, resistivity R, impedance Z, wattage P".
0.81 APEX
The question has just stated clearly that the applied voltage is 12 volts DC.Provided that the power supply is capable of maintaining its output voltage while supplying some current ... i.e. that the effective internal resistance of the power supply is small ... and that the 2.7 ohm resistor is the only external element connected to the power supply's output, the voltage across the resistor is exactly 12 volts DC.The current through the resistor ... supplied by the 12 volt DC supply ... is 12/2.7 = 4.44 Amperes (rounded).The power dissipated by the resistor ... supplied by the DC supply ... is 122 / 2.7 = 53.23 watts !
The capacitor charges up with the current flowing through a resistor. The time taken is well defined by the capacitance and the resistance, and these components control the frequency.
A current limiter. Commonly used in well designed power supplies to make the power supply "Fold over" if output current exceeds a safe value. Commonly use a low value resistor in series with the output, and a circuit that senses the voltage across it. Although the above answer describes a circuit to limit current, the device that limits the amount of current flowing through it is a resistor.
To find the energy dissipated in a resistor, you can use the formula: Energy (current)2 x resistance x time. This formula calculates the energy dissipated in the resistor based on the current flowing through it, the resistance of the resistor, and the time the current flows.
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
A resistor is a conductor that dissipates some of the electrical energy fromthe current flowing through it. The energy dissipated by the resistor is(current through it)2 x (resistance)
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
.205 watts or 205 mw
Here are some practice questions based on Ohm's Law: If a resistor has a resistance of 10 ohms and a current of 2 amperes flowing through it, what is the voltage across the resistor? A circuit has a voltage of 12 volts applied across a resistor with a resistance of 4 ohms. What is the current flowing through the resistor? If a circuit has a current of 0.5 amperes flowing through a resistor with a resistance of 8 ohms, what is the voltage across the resistor? These questions will help you practice applying Ohm's Law to calculate voltage, current, and resistance in electrical circuits.
Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
No. If a voltage is applied across a resistor, a current flows through it.
Current moving through a resistor causes it to heat up because of the flowing electrons bumping into the atoms in the resistor.
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
A resistor gets hot when electricity passes through it because the resistance in the resistor causes some of the electrical energy to be converted into heat energy. This heat energy is dissipated as the resistor resists the flow of electricity, leading to an increase in temperature.
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.